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Artistan's questions

Martin Hope
Artistan
Asked: 2018-05-09 19:28:58 +0800 CST
  • 2

如何连续tail -f记录日志、查找所有文件 ( sed) 并显示 ( cat) 找到的文件

审计日志中的示例数据。

tail -f /var/log/httpd/modsec_audit.log | sed 's/[^\/]*/\./;s/].*$//g'

输出

./apache/20180508/20180508-1428/20180508-142802-WvH6QgoeANwAAMwsFZ4AAAAF
./apache/20180508/20180508-1428/20180508-142803-WvH6QgoeANwAAMwtFfcAAAAG
./apache/20180508/20180508-1428/20180508-142803-WvH6QwoeANwAAMwuFlUAAAAH
./apache/20180508/20180508-1513/20180508-151357-WvIFBQoeANwAAMwnE@4AAAAA
./apache/20180508/20180508-1513/20180508-151357-WvIFBQoeANwAAMwoFD8AAAAB
./apache/20180508/20180508-1516/20180508-151608-WvIFiAoeANwAAMz1FSwAAAAA
./apache/20180508/20180508-1516/20180508-151609-WvIFiQoeANwAAMz2FYIAAAAB
./apache/20180508/20180508-1516/20180508-151611-WvIFiwoeANwAAMz3FeEAAAAC
./apache/20180508/20180508-1516/20180508-151611-WvIFiwoeANwAAMz4Fj4AAAAD
./apache/20180508/20180508-2112/20180508-211205-WvJY9QoeANwAAM1MFCoAAAAA

与回声一起使用

echo "./apache/20180508/20180508-1428/20180508-142802-WvH6QgoeANwAAMwsFZ4AAAAF" | sed 's/[^\/]*/\./;s/].*$//g' | awk '{print $0}' | xargs cat

与猫一起工作

cat /var/log/httpd/modsec_audit.log | sed 's/[^\/]*/\./;s/].*$//g' | awk '{print $0}' | xargs cat

不适用于尾巴...

tail -f /var/log/httpd/modsec_audit.log | sed 's/[^\/]*/\./;s/].*$//g' | awk '{print $0}' | xargs cat

我假设拖尾不起作用，因为脚本永远不会终止，并且sed仍在缓存结果，直到脚本终止。

有没有办法让这项工作持续进行？

sed tail