liyang's questions

代码是：

#!/bin/bash
ips[0]='192.168.0.1'
ips[1]='192.168.0'
ips[2]='255.255.255.256'
ips[3]='123.123.123.123.123'
ips[4]='a.b.c.d'
ips[5]='255.255.255.255'
ips[6]='0.0.0.0'
ips[7]='192.168.1.1'
ips[8]='4.2.2.2'

regex="^((25[0-5]|2[0-4][0-9]|[01][0-9][0-9]|[0-9]{1,2})[.]){3}(25[0-5]|2[0-4][0-9]|[01][0-9][0-9]|[0-9]{1,2})$"

regexVar=$(printf "\033[33mSaved in a VARIABLE\033[0m")
regexStr=$(printf "\033[34mIs a STRING\033[0m")
validOut=$(printf "\033[32mValid\033[0m")
invalidOut=$(printf "\033[31mInvalid\033[0m")
noQuotes="NO quotes"
singleQuotes="Single quotes"
doubleQuotes="Double quotes"

printStyle="%-25s %-10s %-20s %-10s\n"
printTitle=$(printf "${printStyle}" "IP Address" "Validity" "Regex" "Quote Type")
print2ndLine=$(printf "${printStyle}" "====================" "==========" "====================" "==========")

function validIP1a() {
    echo "${printTitle}"
    echo "${print2ndLine}"
    for (( i=0; i<${#ips[@]}; i++ )); do
        if [[ "${ips[i]}" =~ $regex ]]; then
            printf "${printStyle}" "${ips[i]}" "${validOut}" "${regexVar}" "${noQuotes}"
        else
            printf "${printStyle}" "${ips[i]}" "${invalidOut}" "${regexVar}" "${noQuotes}"
        fi
    done
}

validIP1a

输出是：

预期的输出是：

为什么我不能得到预期的结果？如何解决？