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user447274
Asked: 2024-07-18 12:39:31 +0800 CST

在 Linux 系统中以线性模式将特定数量的文件/设备连接在一起

  • 772

为了以线性模式连接 Linux 文件/设备，我有这个dm-joinlinear.sh脚本

在 Linux 系统中以线性模式将文件/设备连接在一起，感谢 telcoM

#!/bin/sh
usage() {
    echo "Usage: ${0##*/} <target name> <component...>" >&2
    exit 64 # EX_USAGE
}
if [ "$1" = "" ] || [ "$1" = "-h" ] || [ "$1" = "-?" ] || [ "$1" = "--help" ]
then
    usage
fi

if [ -e "/dev/mapper/$1" ]
then
    echo "ERROR: target $1 already exists." >&2
    exit 73 # EX_CANTCREAT
fi
MAPNAME="$1"
shift

DMMAP=$(mktemp)
trap "rm -f $DMMAP" EXIT

sum=0
while [ "$1" != "" ]
do
    if [ ! -e "$1" ]
    then
        echo "ERROR: $1 does not exist"
        exit 66 # EX_NOINPUT
    fi
    if [ ! -b "$1" ]
    then
        echo "ERROR: $1 is not a block device"
        exit 69 # EX_UNAVAILABLE
    fi
    srcN="$1"
    sizeN=$(blockdev --getsz "$srcN")
    echo "$sum $sizeN linear $srcN 0" >>$DMMAP
    sum=$(expr $sum + $sizeN)
    shift
done
dmsetup create $MAPNAME < $DMMAP

我运行脚本

./dm-joinlinear.sh one /dev/loop? /dev/loop??

或者

./dm-joinlinear.sh one /dev/mapper/file? /dev/mapper/file??

/dev/loop0 and /dev/mapper/file1 are the same
/dev/loop1 and /dev/mapper/file2 are the same
....
/dev/loop32 and /dev/mapper/file33 are the same

我可以使用以下脚本运行

dm-joinlinear.sh one /dev/loop[0-9] /dev/loop[1-2]? /dev/loop3[0-2]

或者

dm-joinlinear.sh one /dev/loop0 /dev/loop1 /dev/loop2 .... and so on up to /dev/loop32 (to long to write all down here all)

或者与删除“循环”并使用 mapper/file 相同，但从 1 开始而不是从 0 开始

我更喜欢使用 /dev/mapper/file 而不是 /dev/loop

但是我该如何表示dm-joinlinear.sh他们必须加入多少台设备？值是parts.txt

linux

1 个回答

  1. Best Answer

    您可以使用for循环从零迭代到 32，并将设备名称存储在数组中。

    # you don't show the file, there are programmatic ways to acquire this number
n=33

devices=()
for ((i = 0; i < n; i++)); do
  devices+=("/dev/loop${i}")
done

dm-joinlinear.sh one "${devices[@]}"
    • 1

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