Ansible：如何更新与另一个目录键匹配的数组键值

我有以下词典：

question:
  first_run:
    app:
      - answer: null
        name: first_name
        question: What is your First name?
      - answer: null
        name: last_name
        question: What is your Last name?
    core:
      - question: question1
      - question: question2

answer:
  first_name: John
  last_name: Smith

我使用以下任务手动更新question.first_run.app下的答案值，效果很好

- name: Update question variable
  set_fact:
    question:
      first_run:
        app:
          - name: first_name
            question: "What is your First name?"
            answer: "{{ answer.first_name }}"
          - name: last_name
            question: "What is your Last name?"
            answer: "{{ answer.last_name }}"

我还测试了以下任务（对于这种情况，这将是更可取的方法）

- name: "TEST-1"
  set_fact:
    question: "{{ question | combine({'first_run': {'app': question.first_run.app | map('combine', {'answer': update }) | list }}, recursive=True) }}"
  loop: "{{ question.first_run.app }}"
  vars:
    update: "{{ answer[item.name] if item.name in answer.keys() else item.answer }}"

- name: "TEST-2"
  set_fact:
    question: "{{ question | combine({'first_run': {'app': question.first_run.app | map('combine', {'answer': (answer[item.name])})}}, recursive=True) }}"
  loop: "{{ question.first_run.app }}"
  vars:c
    update: "{{ answer | dict2items | selectattr('key', 'in', [item.name]) | map(attribute='value') | first }}"
#    update: "{{ answer[item.name] }}"    # THis also works

但是 TEST-1 和 TEST-2 的输出总是这样的：

question:
  first_run:
    app:
      - answer: Smith
        name: first_name
        question: What is your First name?
      - answer: Smith
        name: last_name
        question: What is your Last name?
    core:
      - question: question1
      - question: question2

我测试的最后一个任务是：
它可以工作，但所需的结果保存在新的 var app_list 下

- name: "TEST-3"
  set_fact:
    question: "{{ question | combine({'first_run': {'app': app_list}}, recursive=True) }}"
  vars:
    app_list: []
  loop: "{{ question.first_run.app }}"
  set_fact:
    app_list: "{{ app_list + [item | combine({'answer': answer[item.name]})] }}"

问题：

我需要更新任务“更新问题变量”，这样我就不必手动放置数组question.first_run.app中的所有这些键

我如何使用循环将question.first_run.app.name与answer.key匹配，以便输出看起来像这样？最好调整 TEST-1 或 TEST-2 或 TEST-3

question:
  first_run:
    app:
      - answer: John
        name: first_name
        question: What is your First name?
      - answer: Smith
        name: last_name
        question: What is your Last name?
    core:
      - question: question1
      - question: question2