我如何从另一个交互式 Bash 脚本中获取 Bash 脚本？

我有一个交互式 Bash 脚本conozcoArrays.sh，，

#!/usr/bin/bash

echo -e "\nGive me their phone number?\n"

read number

TOGOes=("$(find ~/chicas -maxdepth 1 -iname "*$number*" -type d -execdir echo {} + | sed "s;./;${HOME}/chicas/;g")" 
"$(find ~/chulos -maxdepth 1 -iname "*$number*" -type d -execdir echo {} + | sed "s;./;${HOME}/chulos/;g")"
"$(find ~/parejas -maxdepth 1 -iname "*$number*" -type d -execdir echo {} + | sed "s;./;${HOME}/parejas/;g")"
)

for togo in "${TOGOes[@]}"
do
  if [[ $togo != "" ]]; then
    echo $togo
    export togo && cd $togo && return 0
  else
    echo "Haven't found her in my directories." && cd ~/chicas
  fi
done

在我的目录中搜索关键字，如果找到任何内容，它会更改到该目录。出于这个原因，我通常会启动它采购它，就像这样 . ~/CS/SoftwareDevelopment/MySoftware/Bash/pasion/conozcoArrays.sh

我还有另一个 Bash 脚本，todo.sh它引用了“conozcoArrays.sh”：

#!/usr/bin/bash

ita='\e[3m'
end='\e[0m'

echo -e "1. La conozco?
2. Search through websites for a given phone number and create a dossier.
3. {ita}escort-scraper.py{end}"

read ch

if [[ "${ch}" == '1' ]]; then
  . ~/CS/SoftwareDevelopment/MySoftware/Bash/pasion/conozcoArrays.sh
elif [[ "${ch}" == '2' ]]; then
  "${HOME}/CS/SoftwareDevelopment/MySoftware/Python/escorts/search-no.py"
elif [[ "${ch}" == '3' ]]; then
  "${HOME}/CS/SoftwareDevelopment/MySoftware/Python/escorts/escort-scraper.py"
fi

问题是，当我输入1 conozcoArrays.sh 未被评估时，它已启动但似乎没有来源 - 我希望在脚本todo.sh完成后位于不同的目录中，但我没有。我如何conozcoArrays.sh从另一个交互式脚本中获取资源？