如何在 .bashrc 中使用重复代码块

我的 .bashrc 中有 4 个函数，它们是 100 行简单代码

除了函数名称和前 3 行代码是变量之外，这些函数是相同的。

如何将 97 行常见的代码提取到一个单独的实例化块中，然后从 4 个函数中的每一个调用该块？

我尝试制作这些常见的 97 行的通用功能块并从一个非常小的函数调用它，但我无法让它工作。

这是顶部有 3 条唯一行的函数，下面是通用代码

function download_podcaster() 
   
######################################################################
##########                                                  ########## 
#   UNIQUE CODE FOLLOWS  #

#set-up the directory variables

dir_zz="/home/user/podcast_author"  
pone_dir="podcast_author"  
downloads_z="~/Downloads"  

##########   UNIQUE CODE ABOVE                              ##########
##########                                                  ########## 
######################################################################


#  vvvvv COMMON CODE BELOW   vvvvvv


   echo; echo "   .... this output is from youtube-dl ..."; echo

   #download the file
   youtube-dl -f 140 --restrict-filenames -o $dir_zz'/%(title)s.%(ext)s' $1


   #make dir if does not aleready exist
   mkdir -p $dir_zz

   #change to the downloads directory
   cd $dir_zz
   echo
   echo "current dir is:                                   "$(pwd)
   echo
  
   #open the downloads location to show the files with pcmanfm 
   #pcmanfm ~/Downloads &
   pcmanfm $dir_zz &> /dev/null
   
   file_name_z=$(youtube-dl --get-filename --restrict-filenames "$1")
   echo; echo "file name from provided by youtube-dl:            "$file_name_z; echo

   #grab the filename from youtube, and parse it into something useful
   #remove 11 digits before end of file name                
   file_name_z=$(echo $file_name_z | sed 's|...........\.mp4$|.mp4|g' | sed 's|...........\.m4a$|.m4a|g' \
       | sed 's|...........\.webm$|.webm|g' \
       | sed 's|,||g' | sed 's|!||g' | sed 's| |_|g'  |  \
       sed 's|-\.||g' | sed 's|webm||g' | sed 's|mp4||g' | sed 's|\?||g').m4a
           #  remove ,      remove !       replace " " with "_"
           #  remove "-."    remove "webm"
   echo; echo "file name after , ! \" \" ? removed:                "$file_name_z; echo

   var1=$(ls -t | grep -E "^[0-9]{3}" | sort | tail -n  1 | cut --bytes=1-3)
   echo; echo "\$var1 3 digit highest number from file set is:    "$var1; echo
   
   sleep .25
   #create the variable to assign the next file number to front of file name
   next_file_number=$(printf "%03d\n" $((10#$var1+5)))
   echo; echo "File number plus 5 is:                            "$next_file_number; echo

   sleep .25
   #new file name with three digit number in front of filename
   file_name_y=${next_file_number}_${file_name_z}
   echo; echo "concatenated filename is \$file_name_y:            ""$file_name_y"; echo


   #move the old file to the new file name
   mv "$file_name_z" "$file_name_y" 
   echo; echo "                                                  ""$file_name_y"; echo


   #plug phone in. Phone mount point in file system can be seen here
   #echo; cd /var/run/user/$UID/gvfs; ls; echo
   #reference
   #https://askubuntu.com/questions/342319/where-are-mtp-mounted-devices-located-in-the-filesystem
   #
   #How to get to the phone directory on the phone if the directory is dynamically allocated on the 
   #reference  
   #https://askubuntu.com/a/454697/624987
   #phone or changes, use this
   #cd /var/run/user/$UID/gvfs; cd * ; cd *; cd Music; mkdir -p $phone_dir; cd $phone_dir; ls
   #       
   #"cd *" changes to the first directory shown
   
   #grab the directory on the phone in which to place the file
   cd /var/run/user/$UID/gvfs; cd * ; cd *; cd Music; mkdir -p $phone_dir; cd $phone_dir
   phone_dir_long_path=$(pwd)


   echo "  ... now copying the file to the phone -->"; echo
   #copy file to phone
   cp $dir_zz/"$file_name_y" "$phone_dir_long_path"
   echo
   
   #open terminal at directory of files
   gnome-terminal --title="test" --command="bash -c '$phone_dir_long_path; ls; $SHELL'"

   echo
   #open the file name with the default app, usually vlc
   xdg-open $dir_zz/$file_name_y &

   echo
}