比较 bash 变量以查看是否可被 5 整除

各种评论的结论似乎是对原始问题的最简单答案是

if ! (( $COUNTER % 5 )) ; then

您可以使用模算术运算符执行此操作：

#!/bin/sh

counter="$1"
remainder=$(( counter % 5 ))
echo "Counter is $counter"
if [ "$remainder" -eq 0 ]; then
    echo 'its a multiple of 5'
else
    echo 'its not a multiple of 5'
fi

正在使用：

$ ./modulo.sh 10
Counter is 10
its a multiple of 5
$ ./modulo.sh 12
Counter is 12
its not a multiple of 5
$ ./modulo.sh 300
Counter is 300
its a multiple of 5

我还写了一个循环，可能是您正在寻找的？这将遍历从 1 到 600 的每个数字，并检查它们是否是 5 的倍数：

循环.sh

#!/bin/sh
i=1
while [ "$i" -le 600 ]; do
        remainder=$(( i % 5 ))
        [ "$remainder" -eq 0 ] && echo "$i is a multiple of 5"
        i=$(( i + 1 ))
done

输出（缩短）

$ ./loop.sh
5 is a multiple of 5
10 is a multiple of 5
15 is a multiple of 5
20 is a multiple of 5
25 is a multiple of 5
30 is a multiple of 5
...
555 is a multiple of 5
560 is a multiple of 5
565 is a multiple of 5
570 is a multiple of 5
575 is a multiple of 5
580 is a multiple of 5
585 is a multiple of 5
590 is a multiple of 5
595 is a multiple of 5
600 is a multiple of 5

完全按照当前编写的方式回答问题，忽略标题（已编辑）。

要将变量中的整数与许多其他整数值进行比较，其中其他值是提前确定的（不清楚“动态”在问题中的实际含义）：

case "$value" in
    5|10|15|200|400|600)
        echo 'The value is one of those numbers' ;;
    *)
        echo 'The value is not one of those numbers'
esac

当然，这也可以循环完成，

for i in 5 10 15 200 400 600; do
    if [ "$value" -eq "$i" ]; then
        echo 'The value is one of those numbers'
        break
    fi
done

但这使得在不使用某种标志的情况下在给定数字中找不到$value时的情况变得更加困难：

found=0
for i in 5 10 15 200 400 600; do
    if [ "$value" -eq "$i" ]; then
        echo 'The value is one of those numbers'
        found=1
        break
    fi
done

if [ "$found" -eq 0 ]; then
    echo 'The value is not one of those numbers'
fi

或者，清洁工，

found=0
for i in 5 10 15 200 400 600; do
    if [ "$value" -eq "$i" ]; then
        found=1
        break
    fi
done

if [ "$found" -eq 1 ]; then
    echo 'The value is one of those numbers'
else
    echo 'The value is not one of those numbers'
fi

我会亲自去case ... esac执行。