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Accepted
alhelal
Asked: 2018-01-01 18:38:03 +0800 CST

如何在包含前一行模式的文件中添加一个额外的行，该行也有一个模式？

  • 772

我有一个文件 - 

something
\title{\hypertarget{A64L}{A64L(3)}}
something
\title{\hypertarget{MALLOC}{MALLOC(3)}}
something
\title{\hypertarget{STRCMP}{STRCMP(3)}}

in 中的单词{}可以是任何东西，但 consecutive 中的单词相同{}。
我想得到 

something
\title{\hypertarget{A64L}{A64L(3)}}
\addcontentsline{A64L}
something
\title{\hypertarget{MALLOC}{MALLOC(3)}}
\addcontentsline{MALLOC}
something
\title{\hypertarget{STRCMP}{STRCMP(3)}}
\addcontentsline{STRCMP}

我尝试跟随，但失败了。

sed -e /\\\\title\{\\\\hypertarget\{.*\}\{.*\(3\)\}\}/a\\\\\\addcontentsline\{\&\} filename

这是https://tex.stackexchange.com/questions/408244/how-to-make-toc-without-having-any-section-parts-name的扩展

shell-script awk

2 个回答

  1. Best Answer

    我不确定你到底想捕捉什么，但是

    $ sed 's/\\title{\\hypertarget\({[^}]*}\).*/&\n\\addcontentsline\1/' file
something
\title{\hypertarget{A64L}{A64L(3)}}
\addcontentsline{A64L}
something
\title{\hypertarget{MALLOC}{MALLOC(3)}}
\addcontentsline{MALLOC}
something
\title{\hypertarget{STRCMP}{STRCMP(3)}}  
\addcontentsline{STRCMP}
    • 1 
  2. j=`grep -o "{[0-9A-Z]\{4\}}" k1.txt | sed -r "s/\s+//g" | sed '/^$/d'`;
grep -B1 "$j" k1.txt  | sed "/title/s/.*/&\n\\\addcontentsline$j/g";
for i in `grep -o "{[A-Z]\{6\}}" k1.txt`; do
  grep -B1 $i k1.txt| sed "/title/s/.*/&\n\\\addcontentsline$i/g";
done

    输出：

    something
\title{\hypertarget{A64L}{A64L(3)}}
\addcontentsline{A64L}
something
\title{\hypertarget{MALLOC}{MALLOC(3)}}
\addcontentsline{MALLOC}
something
\title{\hypertarget{STRCMP}{STRCMP(3)}}
\addcontentsline{STRCMP}
    • 1

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