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scroobius
Asked: 2017-12-06 23:36:28 +0800 CST

缩短较长的 if/test 字符串比较

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我在 bash 中比较多个字符串。目前我有一个看起来像这样的脚本：

    if [ "$f" != "A-C" ] && [ "$f" != "D-F" ] && [ "$f" != "G-I" ] && [ "$f" != "J-L" ] && [ "$f" != "M-O" ] && [ "$f" != "P-R" ] && [ "$f" != "S-U" ] && [ "$f" != "V-X" ] && [ "$f" != "Y&Z" ] && [ "$f" != "#" ]; then #if f is a directory

我怎样才能缩短这个？

scripting test

1 个回答

  1. Best Answer

    结束了这样的事情：

    [[ "$f" != +(A-C|D-F|G-I|J-L|M-O|P-R|S-U|V-X|Y&Z|#) ]]
    • 0

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