用于在日志文件中查找字符串的 Shell 脚本

只需使用select（bash内置）。

$ help select
select: select NAME [in WORDS ... ;] do COMMANDS; done
    The WORDS are expanded, generating a list of words.  The
    set of expanded words is printed on the standard error, each
    preceded by a number.  If `in WORDS' is not present, `in "$@"'
    is assumed.  The PS3 prompt is then displayed and a line read
    from the standard input.  If the line consists of the number
    corresponding to one of the displayed words, then NAME is set
    to that word.  If the line is empty, WORDS and the prompt are
    redisplayed.  If EOF is read, the command completes.  Any other
    value read causes NAME to be set to null.  The line read is saved
    in the variable REPLY.  COMMANDS are executed after each selection
    until a break command is executed.
$

所以你想要的代码可能是：

read -p 'Enter Customer ID: ' custid
select f in $(find /usr/local/tomcat9/logs -type f -exec grep -q -e "$custid" {} \; -print); do
  vim "$f"
done

请注意，如果您的文件名包含空格，则会中断。也可以看看：

• 为什么循环查找的输出是不好的做法？

但是，如果您select直接从 调用内置函数find，这将轻松处理空格。因此，在我能想到的所有情况下，以下内容实际上都更好：

read -p 'Enter customer ID: ' custid
find /usr/local/tomcat9/logs -type f -exec grep -qe "$custid" {} \; -exec bash -c '
  select f; do vim "$f"; done' find-sh {} +

阅读你的问题提醒我一直想要一个简单的脚本，让我更容易在文件中搜索特定字符串，然后查看包含该字符串的文件之一。在您的脚本和 saga 建议使用数组的基础上，我创建了我的脚本并完成了您的脚本。:)

请注意：这个脚本是 /bin/bash，而不是 /bin/sh，因为我不知道如何让数组在 /bin/sh 中工作...

你的脚本：

#!/bin/bash
# Collect Customer ID as input
read -p "Enter Customer ID: " custid
echo "Searched customer ID $custid found in following logs: "
# Find the customer id as string in specified directory

arr=( $(find /usr/local/tomcat9/logs/ -type f -exec grep -l "$custid" {} \; | sort -r) )

if [ ${#arr[@]} -eq 0 ]; then
    echo "No matches found."
else
    arr+=('Quit')
    select opt in "${arr[@]}"
    do
        case $opt in
            "Quit")
                break
                ;;
            *)
                vim $opt
                break
                ;;
        esac
    done
fi

编辑：虽然上面的脚本可以很好地解决原始问题，但我建立在 Wildcard 的答案之上，因此我的脚本可以处理带有空格的文件并提供各种工具来打开所选文件。

我的脚本：

#!/bin/bash
# Find string in files of given directory (recursively)

read -p "Enter search string: " text
read -p "Enter directory: " directory

#arr=( $(find $directory -type f -exec grep -l "$text" {} \; | sort -r) )
#find $directory -type f -exec grep -qe "$text" {} \; -exec bash -c '

file=$(find $directory -type f -exec grep -qe "$text" {} \; -exec bash -c 'select f; do echo $f; break; done' find-sh {} +;)

if [ -z "$file" ]; then
    echo "No matches found."
else
    echo "select tool:"
    tools=("nano" "less" "vim" "quit")
    select tool in "${tools[@]}"
    do
        case $tool in
            "quit")
                break
                ;;
            *)
                $tool $file
                break
                ;;
        esac
    done
fi