我有查询(这很慢~2,5s):
db.markers.find({ latlng: { '$within': { '$box': [ [ -16, -140 ], [ 75, 140 ] ] } } }).sort({_id: -1}).limit(1000)
当我对此查询运行解释时,我得到
{
"cursor" : "GeoBrowse-box",
"isMultiKey" : false,
"n" : 1000,
"nscannedObjects" : 242331,
"nscanned" : 242331,
"nscannedObjectsAllPlans" : 242331,
"nscannedAllPlans" : 242331,
"scanAndOrder" : true,
"indexOnly" : false,
"nYields" : 1383,
"nChunkSkips" : 0,
"millis" : 2351,
"indexBounds" : {
"latlng" : [ ]
},
"lookedAt" : NumberLong(262221),
"matchesPerfd" : NumberLong(242331),
"objectsLoaded" : NumberLong(242331),
"pointsLoaded" : NumberLong(0),
"pointsSavedForYield" : NumberLong(0),
"pointsChangedOnYield" : NumberLong(0),
"pointsRemovedOnYield" : NumberLong(0),
"server" : "xx:27017"
}
当我删除sort({_id: -1})时,解释给了我(快速查询5 毫秒):
{
"cursor" : "GeoBrowse-box",
"isMultiKey" : false,
"n" : 1000,
"nscannedObjects" : 1000,
"nscanned" : 1000,
"nscannedObjectsAllPlans" : 1000,
"nscannedAllPlans" : 1000,
"scanAndOrder" : false,
"indexOnly" : false,
"nYields" : 0,
"nChunkSkips" : 0,
"millis" : 5,
"indexBounds" : {
"latlng" : [ ]
},
"lookedAt" : NumberLong(1000),
"matchesPerfd" : NumberLong(1000),
"objectsLoaded" : NumberLong(1000),
"pointsLoaded" : NumberLong(0),
"pointsSavedForYield" : NumberLong(0),
"pointsChangedOnYield" : NumberLong(0),
"pointsRemovedOnYield" : NumberLong(0),
"server" : "xx:27017"
}
我在 latlng 上有 2d 索引,在 _id 上有 desc 索引和复合索引。
db.markers.ensureIndex({latlng: '2d', _id:-1})
db.markers.ensureIndex({ latlng: '2d' })
db.markers.ensureIndex({ _id: -1 })
我想要实现的是从最新排序的特定区域获取标记。
任何想法或建议如何在不到2.5 秒的时间内做到这一点?