A.G.Progm.Enthusiast's questions

我有嵌套目录路径，我正在使用以下代码逐部分更改其权限。假设路径为“/apps/sys/utils/prod/sales/apparel/”。
我可以一次性更改其权限，而不是在循环中逐部分执行以获得相同的效果/结果吗？

     import os
     import stat
     def change_permissions(path, new_mode):
        """Change permissions of the directory to new_mode."""
        if not os.path.islink(path):
            original_mode = os.stat(path).st_mode
            os.chmod(path, new_mode)
            oct_perm = oct(new_mode)
            unix_perm = oct_perm[-3: (len(oct_perm))]
            print(f"Permission of {path} changed to {new_mode} = {unix_perm}")
            return original_mode
        return None
 
     
    target_full_path = "/apps/sys/utils/prod/sales/apparel/shirts.csv"
    # Determine the directory path up to which permissions need to be changed
    target_dir = os.path.dirname(target_full_path)
    print(f"The abstract file dir path upto which perm to be changed {target_dir}")
    # Change permissions for the specific directory needed
    original_permissions = []
    current_dir = "/apps/sys/utils/prod"
    for part in target_dir.split(os.sep)[len(dest_root.split(os.sep)):]:
        current_dir = os.path.join(current_dir, part)
        print(f"\n### part = {part} and current_dir = {current_dir}")
        if not os.path.exists(current_dir):
            os.makedirs(current_dir)
            print(f"Created the current_dir = {current_dir}")
        original_mode = change_permissions(current_dir, stat.S_IRWXU | stat.S_IRWXG | stat.S_IRWXO)
        original_permissions.append((current_dir, original_mode))
        print (f"Original mode for current_dir ({current_dir}) is {original_mode}\n")

在我的 TCL 脚本中，我将一个空列表作为参数传递给过程。在过程中，我将值添加到列表中。但在该过程之外，列表的值不会反映出来。如何访问在 proc 中修改的同一列表？

注意：由于某些原因，我不想从过程中返回，为了保持我的要求简单，我没有在这里提到这些原因。

proc addNames { names } {
    lappend names tom
    lappend names harry
    puts $names
}

set names {}
addNames $names 

puts "Outside of proc: names"
puts $names