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Patrick Klitzke's questions

Martin Hope
Patrick Klitzke
Asked: 2023-08-17 16:30:24 +0800 CST
  • 5

我有这个代码：

let routes = match env::var("ENV") {
    Ok(el) => {
        if el == "PROD" {
            routes![upload_image]
        } else {
            routes![get_token, callback, form, upload_image, refresh]
        }
    },
    _ => routes![get_token, callback, form, upload_image, refresh],
};

该函数env::var返回一个Result<String, VarError>. 我想知道我上面的代码是否可以简化如下：

let routes = match env::var("ENV") { // E: mismatched types: this expression has type `Result<std::string::String, VarError>
    Ok("PROD") => { // E: mismatched types: expected `String`, found `&str`
       routes![upload_image]
    },
    _ => routes![get_token, callback, form, upload_image, refresh],
};

String但是，我收到有关“不匹配类型：预期，发现”的错误&str。有没有办法简化这段代码？

rust