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Martin Hope
AlwaysLearning
Asked: 2023-11-07 23:51:23 +0800 CST
  • 6

我有一个 AWS Lambda 函数：

import boto3
import json
import concurrent.futures
from stats import Timer

client = boto3.client('lambda')

def do_lambda():
    timer = Timer()
    response = client.invoke(
        FunctionName = 'arn:aws:lambda:us-east-1:497857710590:function:wherewasit-search',
        InvocationType = 'RequestResponse',
        Payload = json.dumps({'keys': 1}))
    payload = json.loads(json.load(response['Payload'])['body'])
    print(f"Response after {timer.stop()}ms")

def do_work(n_threads):
    timer = Timer()
    with concurrent.futures.ThreadPoolExecutor() as executor:
        futures = []
        for i in range(n_threads):
            futures.append(executor.submit(do_lambda))
        for future in concurrent.futures.as_completed(futures):
            pass
    print(f"Joined all: {timer.stop()}ms")

def lambda_handler(event, context):
    do_work(9)
    return {
        'statusCode': 200,
        'body': json.dumps('Hello from Lambda!')
    }

输出：

Response after 1236ms
Response after 1242ms
Response after 1251ms
Response after 1272ms
Response after 1322ms
Response after 1359ms
Response after 1126ms
Response after 1170ms
Response after 1246ms
Joined all: 2496ms

假设所有线程最多在 1.4 秒内完成，那么在所有线程连接之前又花费了多少秒？

Martin Hope
AlwaysLearning
Asked: 2023-08-22 22:42:50 +0800 CST
  • 5

我将压缩字符串存储在数据库中。我想在 Django Admin 中看到实际的字符串。由于字符串很长，我不希望它们出现在列表视图中，而仅在查看单个项目（行）时出现。所以，我可以定义：

@property
def short_my_field(self):
    return pickle.loads(brotli.decompress(self.my_field))[:80]

@property
def original_my_field(self):
    return pickle.loads(brotli.decompress(self.my_field))

然后我将short_my_field放入list_display. 但是如何original_my_field在查看单个项目时显示呢？

django