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ss77's questions

Martin Hope
ss77
Asked: 2024-09-16 22:52:04 +0800 CST
  • 4

我正在尝试理解静态任务。在这里我理解线程 1、2 和 3 同时发生，并且_time&t_name是任务内部的静态变量。当我模拟代码时，我得到：

[0] Main Thread: Fork join going to start
[0] Main Thread: Fork join has finished
[0] Nested fork has finished
[10] Thread2
[20] Thread2
[30] Thread2

但是，后来我想，既然“Thread2”与其他两个线程共享t_name，那么_time三个线程的共享内存量是不是应该都是 20？我期望的答案是：

[0] Main Thread: Fork join going to start
[0] Main Thread: Fork join has finished
[0] Nested fork has finished
[20] Thread2
[20] Thread2
[20] Thread2

有人能帮助我理解吗？

module tb; 
  initial begin 
    $display("[%0t] Main Thread: Fork join going to start", $time); 
    fork 
      begin 
        fork 
          print(10, "Thread1"); 
          print(20, "Thread2"); 
        join_none
        $display("[%0t] Nested fork has finished", $time); 
      end  
      print(30, "Thread3");  
    join_none
    $display("[%0t] Main Thread: Fork join has finished", $time);
  end 
 
  task print (int _time, string t_name); 
    #(_time) $display ("[%0t] %s", $time, t_name); 
  endtask 
endmodule
static