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Amir reza Riahi's questions

Martin Hope
Amir reza Riahi
Asked: 2024-07-31 23:32:08 +0800 CST
  • 9

在 Python 3.12 中，我们有如下类型别名：

Python 3.12.4+ (heads/3.12:99bc8589f0, Jul 27 2024, 11:20:07) [GCC 12.2.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> type S = str
>>> S
S

根据这种语法，我假设从现在起该词type被视为关键字，但事实并非如此：

>>> type = 2
>>>

并且：

>>> import keyword
>>> keyword.iskeyword('type')
False
python
Martin Hope
Amir reza Riahi
Asked: 2023-11-16 20:53:19 +0800 CST
  • 19

这是 python 3.10 中列表理解的反汇编：

Python 3.10.12 (main, Jun 11 2023, 05:26:28) [GCC 11.4.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import dis
>>> 
>>> dis.dis("[True for _ in ()]")
  1           0 LOAD_CONST               0 (<code object <listcomp> at 0x7fea68e0dc60, file "<dis>", line 1>)
              2 LOAD_CONST               1 ('<listcomp>')
              4 MAKE_FUNCTION            0
              6 LOAD_CONST               2 (())
              8 GET_ITER
             10 CALL_FUNCTION            1
             12 RETURN_VALUE

Disassembly of <code object <listcomp> at 0x7fea68e0dc60, file "<dis>", line 1>:
  1           0 BUILD_LIST               0
              2 LOAD_FAST                0 (.0)
        >>    4 FOR_ITER                 4 (to 14)
              6 STORE_FAST               1 (_)
              8 LOAD_CONST               0 (True)
             10 LIST_APPEND              2
             12 JUMP_ABSOLUTE            2 (to 4)
        >>   14 RETURN_VALUE

据我了解，它创建了一个名为的代码对象listcomp，该对象执行实际迭代并返回结果列表，并立即调用它。我无法理解需要创建一个单独的函数来执行这项工作。这是一种优化技巧吗？

python