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honeybeeham's questions

Martin Hope
honeybeeham
Asked: 2023-08-18 05:49:54 +0800 CST
  • 6

我正在尝试比较两个列表以找出差异和重复项。例子：

- name: Debug
  hosts: "localhost"
  gather_facts: no
  connection: local

  vars: 
    list1: 
      - {name: aBC_SOMEITEM-A01_dEF, type: random, policy: one}
      - {name: aBC_SOMEITEM-A02_dEF, type: random, policy: two}
      - {name: aBC_SOMEITEM-A03_dEF, type: random, policy: three}

    list2: 
      - {name: "SOMEITEM-A01", type: "random", policy: "one"}
      - {name: "SOMEITEM-A02", type: "random", policy: "two"}
      - {name: "SOMEITEM-A03", type: "random", policy: "three"}
      - {name: "SOMEITEM-A03", type: "random", policy: "three"}
      - {name: "SOMEITEM-A04", type: "random", policy: "four"}

    list3: "{{ list1 | map('ansible.builtin.regex_replace', 'aBC_|_dEF', '') | list }}"

  tasks: 
  - debug: 
      msg: |
        {{ list1 | to_yaml(default_flow_style=none) }}
        {{ list2 | to_yaml(default_flow_style=none) }}
        {{ list3 | to_yaml(default_flow_style=none) }}

        {{ list2 | difference(list3) | to_yaml(default_flow_style=none) }}

list3过滤器后的输出map('regex_replace')如下所示：

['{''name'': ''SOMEITEM-A01'', ''type'': ''random'', ''policy'': ''one''}', '{''name'':
    ''SOMEITEM-A02'', ''type'': ''random'', ''policy'': ''two''}', '{''name'': ''SOMEITEM-A03'',
    ''type'': ''random'', ''policy'': ''three''}']
  1. 如何规范化 list3 以使差异的结果输出为
- {name: SOMEITEM-A04, policy: three, type: random}
  1. list2有重复的字典，我怎样才能找到重复的？例如
- {name: "SOMEITEM-A03", type: "random", policy: "three"}

我从这里查看了两个答案，但无法弄清楚 - Ansible: How to getlicate items from list?

（我不介意编写自定义过滤器插件来完成此任务，因为数据集可能非常大）

ansible