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Martin Hope
Pedroski
Asked: 2025-04-23 13:26:23 +0800 CST
  • 5

我可以制作一个这样的 tkinter 按钮：

button1 = ttk.Button(root, text = "Button 1", command=lambda: button_click(button1))

或者像这样循环：

tk.Button(root, text=f"Button {i}", command=lambda x=i: button_click(x)).pack()

但是第二个按钮没有像 button1 那样的变量名。因此，我无法通过名称访问它：

def button_click(button):
        button_text = button.cget('text')
        ttk.Label(root, text = button_text).pack()

或者在这样的循环中创建时，第二个按钮实际上是否具有 tkinter 默认名称？

tkinter
Martin Hope
Pedroski
Asked: 2024-02-24 21:31:00 +0800 CST
  • 3

我有这个代码，但我实际上没有收到电子邮件文本。

我必须解码电子邮件文本吗？

import sys
import imaplib
import getpass
import email
import email.header
from email.header import decode_header
import base64

def read(username, password, sender_of_interest):
    # Login to INBOX
    imap = imaplib.IMAP4_SSL("imap.mail.com", 993)
    imap.login(username, password)
    imap.select('INBOX')
    # Use search(), not status()
    # Print all unread messages from a certain sender of interest
    if sender_of_interest:
        status, response = imap.uid('search', None, 'UNSEEN', 'FROM {0}'.format(sender_of_interest))
    else:
        status, response = imap.uid('search', None, 'UNSEEN')
    if status == 'OK':
        unread_msg_nums = response[0].split()
    else:
        unread_msg_nums = []
    data_list = []
    for e_id in unread_msg_nums:
        data_dict = {}
        e_id = e_id.decode('utf-8')
        _, response = imap.uid('fetch', e_id, '(RFC822)')
        html = response[0][1].decode('utf-8')
        email_message = email.message_from_string(html)
        data_dict['mail_to'] = email_message['To']
        data_dict['mail_subject'] = email_message['Subject']
        data_dict['mail_from'] = email.utils.parseaddr(email_message['From'])
        #data_dict['body'] = email_message.get_payload()[0].get_payload()
        data_dict['body'] = email_message.get_payload()
        data_list.append(data_dict)
    print(data_list)
    # Mark them as seen
    #for e_id in unread_msg_nums:
        #imap.store(e_id, '+FLAGS', '\Seen')
    imap.logout()    
    return data_dict

所以我这样做：

print('Getting the email text bodiies ... ')
emailData = read(usermail, pw, sender_of_interest)
print('Got the data!')
for key in emailData.keys():
    print(key, emailData[key])

输出是：

mail_to [email protected]
mail_subject 获取 json 文件
mail_from ('Pedro Rodriguez', ' [email protected] ')
body [<email.message.Message object at 0x7f7d9f928df0>, <email.message.Message object at 0x7f7d9f928f70>]

如何实际获取电子邮件文本？

尝试了该建议，但似乎失败了，因为它是多部分的，并带有附加的文本文件：

def read(username, password, sender_of_interest):
    # Login to INBOX
    imap = imaplib.IMAP4_SSL("imap.qq.com", 993)
    imap.login(username, password)
    imap.select('INBOX')
    # Use search(), not status()
    # Print all unread messages from a certain sender of interest
    if sender_of_interest:
        status, response = imap.uid('search', None, 'UNSEEN', 'FROM {0}'.format(sender_of_interest))
    else:
        status, response = imap.uid('search', None, 'UNSEEN')
    if status == 'OK':
        unread_msg_nums = response[0].split()
    else:
        unread_msg_nums = []
    data_list = []
    for e_id in unread_msg_nums:
        data_dict = {}
        e_id = e_id.decode('utf-8')
        _, response = imap.uid('fetch', e_id, '(RFC822)')
        email_message = email.message_from_bytes(response[0][1], policy=default)
        #html = response[0][1].decode('utf-8')
        #email_message = email.message_from_string(html)
        data_dict['mail_to'] = email_message['To']
        data_dict['mail_subject'] = email_message['Subject']
        data_dict['mail_from'] = email.utils.parseaddr(email_message['From'])
        #data_dict['body'] = email_message.get_payload()[0].get_payload()
        #data_dict['body'] = email_message.get_payload()[0]
        data_dict['body'] = email_message.get_body('html', 'text').get_payload(decode=True)
        data_list.append(data_dict)
    print(data_list)
    # Mark them as seen
    #for e_id in unread_msg_nums:
        #imap.store(e_id, '+FLAGS', '\Seen')
    imap.logout()    
    return data_dict

得到这个错误：

emailData = read(usermail, pw, sender_of_interest) 回溯（最近一次调用）：文件“/usr/lib/python3.10/idlelib/run.py”，第 578 行，在 runco​​de exec(code, self.locals) 文件中“<pyshell#126>”，第 1 行，文件“<pyshell#125>”，第 29 行，读取 TypeError: MIMEPart.get_body() 采用 1 到 2 个位置参数，但给出了 3 个

我还导入了 BeautifulSoup 以从 html 中获取文本：

from bs4 import BeautifulSoup 

# this seems to work
def read(username, password, sender_of_interest):
    # Login to INBOX
    imap = imaplib.IMAP4_SSL("imap.qq.com", 993)
    imap.login(username, password)
    imap.select('INBOX')
    # Use search(), not status()
    # Print all unread messages from a certain sender of interest
    if sender_of_interest:
        status, response = imap.uid('search', None, 'UNSEEN', 'FROM {0}'.format(sender_of_interest))
    else:
        status, response = imap.uid('search', None, 'UNSEEN')
    if status == 'OK':
        unread_msg_nums = response[0].split()
    else:
        unread_msg_nums = []
    data_list = []
    for e_id in unread_msg_nums:
        data_dict = {}
        e_id = e_id.decode('utf-8')
        _, response = imap.uid('fetch', e_id, '(RFC822)')
        email_message = email.message_from_bytes(response[0][1], policy=default)
        html = response[0][1].decode('utf-8')
        data_dict['mail_to'] = email_message['To']
        data_dict['mail_subject'] = email_message['Subject']
        data_dict['mail_from'] = email.utils.parseaddr(email_message['From'])
        body = email_message.get_body(('html', 'text')).get_payload(decode=True)
        soup = BeautifulSoup(body, 'html.parser')
        div_bs4 = soup.find('div')
        text = div_bs4.string
        data_dict['body'] = text
        data_list.append(data_dict)
    print(data_list)
    # Mark them as seen
    #for e_id in unread_msg_nums:
        #imap.store(e_id, '+FLAGS', '\Seen')
    imap.logout()    
    return data_dict

body 的输出现在是：

'body': '你能得到附件吗？

现在我需要做的就是获取附件！

python
Martin Hope
Pedroski
Asked: 2023-12-02 18:15:57 +0800 CST
  • 5

尝试设置表格列宽度，但我不能。

根据我在这里查找的线程，类似的东西应该设置单元格宽度。不确定 EMU 是什么，但我相信 Mm(10) 将 10mm 转换为 EMU。

table.cell(0,0).width = 1097280

我做了一个非常简单的表，只有一行。我认为这应该设置列宽，但我得到的只是 3 个等宽列！尝试了很多不同的方法。

编辑：忘记输入数据

from docx import Document
from docx.shared import Pt, Mm, Cm, Inches
from docx.enum.table import WD_ALIGN_VERTICAL, WD_TABLE_ALIGNMENT


filename = "/home/pedro/myPython/docxFiles/example_table.docx"
doc = Document()
heading = 'Shiny new but awkward table" \n\n'
doc.add_heading(heading, 4)
table = doc.add_table(rows=1, cols=3)
table.alignment = WD_TABLE_ALIGNMENT.CENTER
table.autofit = False
table.allow_autofit = False
table.style = 'Table Grid'
headers = ["Name", "Age", "Occupation"]
widths = [15.9, 11.8, 26.7]
for col, col_data in enumerate(headers):
    print(col, col_data)
    table.cell(0,col).text = col_data
   
for col, width in enumerate(widths):
   print(col, width)
   table.cell(0, col).width = Mm(widths[col])
doc.save(filename)

当然，我想获取列中的最大字符串宽度并将列宽度设置为该宽度或最大值，但目前即使设置绝对值对我来说也不起作用。

我究竟做错了什么？也许是因为我用 Libre Office 打开它，而不是 MS Word？？

有什么建议吗？

python-docx