Scala 读取列表类中的参数值的问题

因此，您有一个带有签名的函数

def yourFunction(param1: Type1, param2: Type2): List[Camp]

根据提供的示例，我假设以下类是这样定义的

val UG = "UG"
case class Target(floats: List[Float])
case class Page(x: Int, y: Int, a: Int, b: Int)
case class Camp(x: Int, ug: String, target: Target, pages: List[Page], y: Double)

如果您只想获取遵循某些特定规则的列表中元素的值，则可以使用find返回Option。 如果找到元素，它将为Some，否则为None。

val camps: List[Camp] = yourFunction(param1, param2) // your function returning

val maybeElementFound: Option[Camp] = camps
  .find(camp =>                           // we try to find a `camp` element that follow some criteria
    camp.x == 2                           // x == 2
      && camp.y == 8                      // y == 8
      && camp
          .pages                          // pages is a list, so we need to use some of the methods provided by that class
          .contains(Page(2,4,600,150))    // contains returns true if the element passed exist, otherwise returns false
  )

maybeElementFound match {
  case Some(campFound) => // ... the logic when the element is found
  case None => // ... the logic when the element is not found 
}