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Accepted
danday74
Asked: 2024-08-01 06:17:11 +0800 CST

如何使用正则表达式组从字符串中提取所有所需的值？[重复]

  • 772

我有一个字符串：

const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`

我正在尝试提取这些值：

[ "9'2", "8'", "7' 11" ]

我想使用正则表达式组来实现这一点（我的实际代码要复杂得多，而正则表达式组会简化事情），但我的正则表达式不太管用。如何才能让下面代码片段中的所有 3 个测试都返回 true？

const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`

const regex = /(\d+' ?\d+)"/g

const matches = [...str.matchAll(regex)]

const actual = matches.map(x => x[1])

const expected = [ "9'2", "8'", "7' 11" ]

console.log(actual) // [ "9'2", "7' 11" ]

// tests
console.log(actual[0] === expected[0]) // true
console.log(actual[1] === expected[1]) // false
console.log(actual[2] === expected[2]) // false

javascript

2 个回答

  1. Best Answer

    您可以使用这种模式：

    [0-9]+'(?:\s*[0-9]+")?


    const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`;

const regex = /[0-9]+'(?:\s*[0-9]+")?/g;

const matches = [...str.matchAll(regex)];

const actual = matches.map((x) => x[0]);
const expected = [`9'2"`, `8'`, `7' 11"`];

console.log(actual[0] === expected[0]); 
console.log(actual[1] === expected[1]); 
console.log(actual[2] === expected[2]);

    • 0

  2. 在@user24714692 的帮助下，我又发现了一些同样有效的变体！

    const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`

const regexes = [
  /[0-9]+'(?:\s*[0-9]+")?/g,
  /\d+'(?: *\d+")?/g,
  /\d+'(?: ?\d+")?/g
]

for (let regex of regexes) {
  const matches = [...str.matchAll(regex)]

  const actual = matches.map(x => x[0])
  const expected = [ `9'2"`, `8'`, `7' 11"` ]

  console.log(actual)
  
  // tests
  console.log(actual[0] === expected[0]) // true
  console.log(actual[1] === expected[1]) // true
  console.log(actual[2] === expected[2]) // true
}

    • 0

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