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Accepted
kuninox
Asked: 2023-11-28 15:25:53 +0800 CST

如果多行适合某个模式，则将其打印为单行

  • 772

我有一个包含多行的文件，并且仅当它们符合特定模式时我才想连接行。我知道我可以加入这些行，例如：

$ cat input.txt
1
00:02:34,654 --> 00:02:36,554
Sean, let's go.

2
00:02:38,358 --> 00:02:40,724
Yeah. Detective. we got
a possible 1 87 out on Route 59.

3
00:03:04,584 --> 00:03:06,051
Right this way.

4
00:05:01,301 --> 00:05:03,269
How long has this been here?./
Tuesday.

$ cat input.txt | perl -00 -lpe '$i = 0; s/\n/(++$i > 2) ? " " : "\n"/ge'
1
00:02:34,654 --> 00:02:36,554
Sean, let's go.

2
00:02:38,358 --> 00:02:40,724
Yeah. Detective. we got a possible 1 87 out on Route 59.

3
00:03:04,584 --> 00:03:06,051
Right this way.

4
00:05:01,301 --> 00:05:03,269
How long has this been here?./ Tuesday.

但是，我该如何解决该线是否符合模式（仅当它们有一个'/'）？所以在这种情况下，我想要实现的输出是：

1
00:02:34,654 --> 00:02:36,554
Sean, let's go.

2
00:02:38,358 --> 00:02:40,724
Yeah. Detective. we got
a possible 1 87 out on Route 59.

3
00:03:04,584 --> 00:03:06,051
Right this way.

4
00:05:01,301 --> 00:05:03,269
How long has this been here?./ Tuesday.
linux

1 个回答

  1. Best Answer
    sed '/\//{N;s/\n/ /;}'
    • /\//如果该行包含/
    • N添加换行符和下一行
    • s/\n/ /用 spce 替换换行符。
    • 0

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