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Accepted
Alexander Farber
Asked: 2023-10-15 17:24:35 +0800 CST

尝试选择随机字典条目时出错：无法读取属性 Symbol(Symbol.iterator)

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当尝试从 Javascript 对象中选择随机单词及其描述时WORDS，不幸的是打印了一个错误：

"use strict";

const WORDS = {
  "one": "Word description 1",
  "two": "Word description 2",
  "three": "Word description 3",
  "four": "",
  "five": "Word description 5",
  "six": "Word description 6",
  "seven": "Word description 7"
};

function randomWord() {
  // select all words with a description
  const entries = Object.entries(WORDS)
    .filter((word, description) => description && description.length > 2);

  console.log(entries);

  // a quicker way of doing parseInt(entries.length * Math.random(), 0)
  const [word, description] = entries[entries.length * Math.random() << 0];
  console.log(word + ': ' + description);
}

randomWord();
randomWord();

这里是JsFiddle中的相同代码。

使用Object.entries()和filter()的组合不是正确的方法吗？

javascript

1 个回答

  1. Best Answer

    正如评论中提到的，您的过滤器中存在语法错误。

    这是一个使用Fisher-Yates来打乱过滤后的数组的工作版本，之后您可以获取条目，直到数组为空

    const fy = (a,b,c,d) => {c=a.length;while(c)b=Math.random()*c--|0,d=a[c],a[c]=a[b],a[b]=d}

const WORDS = {
  "one": "Word description 1",
  "two": "Word description 2",
  "three": "Word description 3",
  "four": "",
  "five": "Word description 5",
  "six": "Word description 6",
  "seven": "Word description 7"
};

// Use object entries array and filter it
let entries = Object.entries(WORDS)
  .filter(([word, description]) => description && description.length > 2);

if (entries.length) {
  fy(entries); // Shuffle the entries array
}

const getWord = (entries) => entries.length > 0 ? entries.pop() : "No more entries";

console.log(getWord(entries));
console.log(getWord(entries));

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