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elanozturk
Asked: 2017-12-25 03:26:11 +0800 CST

多个文件文本替换为 sed

  • 772

我尝试用sed但不知道如何用多个文件替换文本文件中的一些文本。
我用：

sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g /path/to/file/target_text_file

在处理多个文件之前，我使用以下命令在文本文件中打印了目标文本文件的路径：

find /path/to/files/ -name "target_text_file" > /home/user/Desktop/target_files_list.txt

现在我想sed按照target_files_list.txt.

bash

3 个回答

  1. Best Answer

    您可以使用循环遍历文件while ... do：

    $ while read i; do printf "Current line: %s\n" "$i"; done < target_files_list.txt

    在你的情况下，你应该printf ...用sed你想要的命令替换。

    $ while read i; do sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g' "$i"; done < target_files_list.txt

    但是，请注意，您只能使用以下方法实现您想要的find：

    $ find /path/to/files/ -name "target_text_file" -exec sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g' {} \;

    您可以通过运行阅读更多关于-exec选项的信息man find | less '+/-exec '：

       -exec command ;

          Execute command; true if 0 status is returned.  All
          following arguments to find are taken to be arguments to
          the command until an argument consisting of `;' is
          encountered.  The string `{}' is replaced by the current
          file name being processed everywhere it occurs in the
          arguments to the command, not just in arguments where it
          is alone, as in some versions of find.  Both of these
          constructions might need to be escaped (with a `\') or
          quoted to protect them from expansion by the shell.  See
          the EXAMPLES section for examples of the use of the
          -exec option.  The specified command is run once for
          each matched file.  The command is executed in the
          starting directory.  There are unavoidable security
          problems surrounding use of the -exec action; you should
          use the -execdir option instead.

    编辑：

    正如用户 terdon和甜点在评论中正确指出的那样，必须使用-rwith ，read因为它可以正确处理反斜杠。它也被报道shellcheck：

    $ cat << EOF >> do.sh
#!/usr/bin/env sh
while read i; do printf "$i\n"; done < target_files_list.txt
EOF
$ ~/.cabal/bin/shellcheck do.sh

In do.sh line 2:
while read i; do printf "\n"; done < target_files_list.txt
      ^-- SC2162: read without -r will mangle backslashes.

    所以应该是：

    $ while read -r i; do sed -i -- 's/SOME_TEXT/SOME_TEXT_TO_REPLACE/g' "$i"; done < target_files_list.txt
    • 7

  2. 一种方法是使用xargs：

    xargs -a target_files_list.txt -d '\n' sed -i -- 's/SOME_TEXT/TEXT_TO_REPLACE/g'

    来自man xargs：

       -a file, --arg-file=file
          Read items from file instead of standard input.  

   --delimiter=delim, -d delim
          Input  items  are  terminated  by  the specified character.  The
          specified delimiter may be a single character, a C-style charac‐
          ter  escape  such as \n, or an octal or hexadecimal escape code.
    • 3

  3. 只需使用一个for循环。

    IFS=$'\n' # Very important! Splits files on newline instead of space.

for file in $(cat files.txt); do
    sed ...
done

    请注意，如果您遇到名称中带有换行符 (!) 的任何文件，您将遇到问题。（：

    • 2

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