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Accepted
masoud hanifehzadeh
Asked: 2023-04-25 08:49:00 +0800 CST

在特殊字符后找到一个数字并将其乘以 awk

  • 772

我有一个文件：

"UDP", "x", 12880, "any", "any", x, 0.0.0.0/0, 0.0.0.0/0, {85000, drop, -1, fast+dsample:1000}, {1m, alert, -1, none}

如何更改“{”之后的 85000 数字并将其乘以一个值以将其减去 awk。像：85000*0.75= 63,750 最后一行应该是：

"UDP", "x", 12880, "any", "any", x, 0.0.0.0/0, 0.0.0.0/0, {63750, drop, -1, fast+dsample:1000}, {1m, alert, -1, none}
text-processing

1 个回答

  1. Best Answer

    使用任何 awk（例如，mawk）：

    mawk 'match($0,/{[0-9]+/) {
  d = substr($0,RSTART+1,RLENGTH)
  $0 = substr($0,1,RSTART) 0.75*d substr($0,RSTART+RLENGTH)
} 1' file
"UDP", "x", 12880, "any", "any", x, 0.0.0.0/0, 0.0.0.0/0, {63750, drop, -1, fast+dsample:1000}, {1m, alert, -1, none}

    使用 GNU awk：

    gawk 'match($0,/([^{]*{)([0-9]+)(.*)/,a){$0 = a[1] 0.75*a[2] a[3]} 1' file
"UDP", "x", 12880, "any", "any", x, 0.0.0.0/0, 0.0.0.0/0, {63750, drop, -1, fast+dsample:1000}, {1m, alert, -1, none}

    或者，使用 perl

    perl -pe 's/(?<={)\d+/0.75 * $&/e' file
"UDP", "x", 12880, "any", "any", x, 0.0.0.0/0, 0.0.0.0/0, {63750, drop, -1, fast+dsample:1000}, {1m, alert, -1, none}
    • 1

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