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code-8
Asked: 2020-06-04 14:24:48 +0800 CST

多个别名触发相同的功能

  • 772

我正在尝试创建一个函数，但我想通过任一别名触发：debugApp，debugApi

而不是创建 2 个函数来做同样的事情

debugApp() {

    #update .env to generate log
    sed -i -e 's/.*API_DEBUG=.*/API_DEBUG=true/g' /Users/jdoe/laravel/.env
    echo "-----------------------"
    cat /Users/jdoe/laravel/.env | grep API_DEBUG


    #remove old logs
    # rm -rf /Users/jdoe/laravel/storage/logs/*
    ls /Users/jdoe/laravel/storage/logs/

    #display correct logs
    tail -f /Users/jdoe/laravel/storage/logs/laravel-$(date "+%Y-%m-*").log
}


debugApi() {

    #update .env to generate log
    sed -i -e 's/.*API_DEBUG=.*/API_DEBUG=true/g' /Users/jdoe/laravel/.env
    echo "-----------------------"
    cat /Users/jdoe/laravel/.env | grep API_DEBUG


    #remove old logs
    # rm -rf /Users/jdoe/laravel/storage/logs/*
    ls /Users/jdoe/laravel/storage/logs/

    #display correct logs
    tail -f /Users/jdoe/laravel/storage/logs/laravel-$(date "+%Y-%m-*").log
}

有没有更好的办法？

command-line bash bashrc alias functions

1 个回答

  1. Best Answer

    我这样做是为了让它工作

    别名 debugApp=debugApi

    • 0

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