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arash deilami
Asked: 2018-08-24 06:12:55 +0800 CST

如何使用 grep 在文本文件中搜索包含列表中所有单词且没有特定顺序的行？[复制]

  • 772

我们如何使用grep获取包含一组单词的行，而单词的顺序并不重要，尽管行应该包含搜索中提到的所有单词？

我已经通过分阶段搜索（使用管道，将输出保存在临时文件中，然后再次搜索）来做到这一点，但我想知道我是否可以一次尝试做到这一点。

这是一个示例；我想在下面的行中搜索包含sample、words、list的行：

it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
line with no search keyword here.
list the sample files.
something completely different.

并得到这个结果：

it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
command-line grep

2 个回答

  1. Best Answer

    简单的方法是多次调用grep： 

    grep sample testfile.txt | grep words | grep list

    一个示范： 

    echo -e "it's a sample test file for a list of words.\nlist of words without a specific order, it's a sample. \nline with no search keyword here. \nlist the sample words. \nsomething completely different." | grep sample | grep words | grep list
it's a sample test file for a list of words.
list of words without a specific order, it's a sample. 
list the sample words.
    • 4

  2. 您可以在 Perl-regex ( ) 中使用前瞻-P：

    grep -P '(?=.*list)(?=.*words)(?=.*sample)'

    例子：

    echo "it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
line with no search keyword here.
list the sample words.
sample line with only two of the keywords inside.
something completely different." \
| grep -P '(?=.*list)(?=.*words)(?=.*sample)'

it's a sample test file for a list of words.
list of words without a specific order, it's a sample.
list the sample words.

    （通过）

    使用agrep( sudo apt install agrep) 您可以链接多个模式：

    agrep "sample;words;list"

    （通过）

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