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Accepted
Shailesh Sutar
Asked: 2018-08-08 06:03:03 +0800 CST

在 shell 脚本中定义数组

  • 772

我正在尝试在我的 shell 脚本中定义数组，其内容如下

cassandra_hosts=(cassandra1.test-dev.local cassandra2.test-dev.local cassandra3.test-dev.local)

但它不允许我定义它并给出如下错误。

-bash: syntax error near unexpected token `cassandra1.test-dev.local'

我尝试了以下组合来定义它，但它们不起作用。

cassandra-hosts=('cassandra1.test-dev.local' 'cassandra2.test-dev.local' 'cassandra3.test-dev.local')
cassandra-hosts=("cassandra1.test-dev.local" "cassandra2.test-dev.local" "cassandra3.test-dev.local")
cassandra-hosts=(cassandra1\.test-dev\.local cassandra2\.test-dev\.local cassandra3\.test-dev\.local)
cassandra-hosts=('cassandra1\.test-dev\.local' 'cassandra2\.test-dev\.local' 'cassandra3\.test-dev\.local')
cassandra-hosts=("cassandra1\.test-dev\.local" "cassandra2\.test-dev\.local" "cassandra3\.test-dev\.local")
cassandra-hosts=("cassandra1\.test-dev\.local" "cassandra2\.test-dev\.local" "cassandra3\.test-dev\.local")
cassandra-hosts=('cassandra1\.test-dev\.local' 'cassandra2\.test-dev\.local' 'cassandra3\.test-dev\.local')

我究竟做错了什么？

linux

1 个回答

  1. Best Answer
    bash-4.2$ cassandra_hosts="cassandra1.dev-internal.local cassandra2.dev-internal.local cassandra3.dev-internal.local"
bash-4.2$ for i in $cassandra_hosts; do echo "host: $i"; done
host: cassandra1.dev-internal.local
host: cassandra2.dev-internal.local
host: cassandra3.dev-internal.local
    • 1

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