如何输出具有特殊模式的列

这将完全按照您的意愿进行

#!/bin/bash
array=(
[0]="scatman"
[1]="batman"
[2]="superman"
)
count=0
while read line; do
    for i in "${array[@]}";
    do
    if [[ $count == 3  ]]; then
    count=0
    fi
    if [[ $line == ${array[$count]} ]]; then
    #echo "$line"
    printf "%s " $line

    # uncomment if you want every word on a new line
    #echo "$line" >> newfile.txt # each word on a line
    #or
    # uncomment if you want all will be on one line
    #printf "%s " $line >> newfile.txt

    count=$((count+1))
    else
    continue
    fi

    done

done < file.txt #this is your original file

将在新行上打印出每个单词，如下所示：

scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman
batman
superman
scatman

或者像这样的一行：

scatman batman superman scatman batman superman scatman batman superman scatman batman superman scatman batman superman scatman

这可以通过grepand来完成awk：

cat words.txt |
grep -E 'scatman|batman|superman' |
awk '{
      last_word = cur_word
      cur_word = $0
      if (cur_word == last_word)
        next
      else
        print $0
      }' < word.list 

允许一个扩展的grep -E正则表达式，让您可以|用作or搜索目标。awk代码查找重复的单词并跳过它们。

如果您愿意，您可以在一行中完成所有这些操作：

cat words.txt | grep -E 'scatman|batman|superman' | awk '{ last_word = cur_word; cur_word = $0; if (cur_word == last_word) next; else print $0 }' < word.list`