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Accepted
Mircea Vutcovici
Asked: 2016-09-22 06:10:00 +0800 CST

剧本中的Ansible反斜杠转义

  • 772

如何在 ansible playbooks 中正确转义反斜杠？

我正在尝试搜索并替换密码中的反斜杠，但我什至无法在 regex_replace jinja2 过滤器中添加反斜杠作为字符串。我正在使用 ansible 版本 2.1.1.0。

这是问题的一个例子：

$ cat jinja2-escape-test.yml
---
- hosts: localhost
  gather_facts: no

  vars:
    password: '\Udl5DoQfa3Uy_:1sbcE'

  tasks:

  - debug: var=password

  - name: Escape root password - working
    set_fact: "password_escaped={{ password | regex_replace ('U','\\X') }}"

  - name: Escape root password - not working
    set_fact: "password_escaped={{ password | regex_replace ('U','\\') }}"

  - debug: msg=password_escaped={{ password_escaped }}

# vim:et:sw=2:ts=2:sts=2:

$ ansible-playbook jinja2-escape-test.yml
ERROR! failed at splitting arguments, either an unbalanced jinja2 block or quotes: password_escaped={{ password | regex_replace ('U','\') }}

The error appears to have been in '/home/mot/build-dashboards/jinja2-escape-test.yml': line 15, column 5, but may
be elsewhere in the file depending on the exact syntax problem.

The offending line appears to be:


  - name: Escape root password - not working
    ^ here
ansible ansible-playbook

1 个回答

  1. Best Answer

    您在此处混合语法样式并且引用设置错误：

      - name: Escape root password - working
    set_fact: "password_escaped={{ password | regex_replace ('U','\\X') }}"

    应该是：

      - name: Escape root password - working
    set_fact:
      password_escaped: "{{ password | regex_replace ('U','\\X') }}"

    或者：

      - name: Escape root password - working
    set_fact: password_escaped="{{ password | regex_replace ('U','\\X') }}"

    您可能想检查引用是否比 regex_replace 更适合您的需求。像这样使用它：

      - name: Escape root password - working
    set_fact:
      password_escaped: "{{ password | quote }}"
    • 5

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