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elliotp
Asked: 2015-07-01 07:51:18 +0800 CST

Crontab 一周中的某些天发生冲突

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我已经在 centos 6 crontab 上设置了备份轮换，一个脚本应该在周一到周六运行，另一个在周日运行，而不是在每月 1 日。然而，每周（仅限周日）脚本每晚都在运行，而每日脚本则在周日运行。由 cron.log 确认

#Daily - Midnight, Mon-Sat, Not on the 1st of the Month
0 0 2-31 * 1-6 script_daily

#Weekly - Midnight, Sunday, Not on the 1st of the Month
0 0 2-31 * 0 script_weekly

我无法弄清楚我做错了什么？

编辑：我已经从 cron 日志中提取了相关行。28 日是星期天。

Jun 28 00:00:01 backup CROND[2000]: (root) CMD (script_daily)
Jun 28 00:00:01 backup CROND[2004]: (root) CMD (script_weekly)
Jun 29 00:00:01 backup CROND[9438]: (root) CMD (script_daily)
Jun 29 00:00:01 backup CROND[9443]: (root) CMD (script_weekly)
Jun 30 00:00:02 backup CROND[6893]: (root) CMD (script_daily)
Jun 30 00:00:02 backup CROND[6898]: (root) CMD (script_weekly)
linux

1 个回答

  1. Best Answer

    手册页

    If you  spec-
ify  both  a day in the month and a day of week, it will be interpreted
as the Nth such day in the month.

    [...]

    To request the last Monday, etc.  in a month, ask for  the  "5th"  one.
This  will  always  match the last Monday, etc., even if there are only
four Mondays in the month:


     # run at 11 am on the first and last Mon, Tue, Wed of each month
     0 11 1,5 * mon-wed date

When the fourth Monday in a month is the last, it  will  match  against
both  the "4th" and the "5th" (it will only run once if both are speci-
fied).

    简而言之...

    0 0 2-31 * 1-6 script_daily

    每个月的第二个到最后一个星期一/星期二/星期三/星期四/星期五/星期六

    0 0 2-31 * 0 script_weekly

    每个月的第二个到最后一个星期日

    在我的脑海中，我怀疑正确的答案是“教你的脚本在看到它们在本月 1 日运行时立即退出”，然后运行你的工作

    0 0 * * 1-6 script_daily
0 0 * * 0 script_weekly
    • 0

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