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R. S.
Asked: 2013-02-11 14:54:36 +0800 CST

Tomcat url rewrite fails with 404，但是直接浏览返回200

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我部署了一个 Web 应用程序webapps/appname，我正在尝试添加重写规则example.org/appname-slow以重写为example.org/appname?delay=1. 我有以下内容webapps/ROOT/WEB-INF/web.xml

<filter>
    <filter-name>UrlRewriteFilter</filter-name>
    <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>

    <init-param>
        <param-name>confReloadCheckInterval</param-name>
        <param-value>0</param-value>
    </init-param>

    <init-param>
        <param-name>statusEnabledOnHosts</param-name>
        <param-value>*</param-value>
    </init-param>

    <init-param>
        <param-name>logLevel</param-name>
        <param-value>sysout:DEBUG</param-value>
    </init-param>

</filter>

<filter-mapping>
    <filter-name>UrlRewriteFilter</filter-name>
    <url-pattern>/*</url-pattern>
    <dispatcher>REQUEST</dispatcher>
    <dispatcher>FORWARD</dispatcher>
</filter-mapping>

和以下内容webapps/ROOT/WEB-INF/urlrewrite.xml：

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 4.0//EN"
    "http://www.tuckey.org/res/dtds/urlrewrite4.0.dtd">

<urlrewrite use-context="true">

    <rule match-type="regex">
        <from>^/appname-slow/(.*)$</from>
        <to type="forward" qsappend="true">/appname/$1?delay=1</to>
    </rule>

</urlrewrite>

但是当我转到新网址时，我得到：

HTTP Status 404 - /appname/
type Status report
message /appname/
description The requested resource is not available.

并直接/appname/按预期工作。

在context.xml我有

<Context crossContext="true">

这是catalina.out日志输出

org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: starting conf reload check
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: conf is not modified
org.tuckey.web.filters.urlrewrite.utils.ServerNameMatcher DEBUG: looking for hostname match on current server name test.example.org
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: checking for status path on /appname-slow/
org.tuckey.web.filters.urlrewrite.UrlRewriter DEBUG: processing request for /appname-slow/
org.tuckey.web.filters.urlrewrite.RuleBase DEBUG: Rule 0 run called with /appname-slow/
org.tuckey.web.filters.urlrewrite.RuleBase DEBUG: matched "from"
org.tuckey.web.filters.urlrewrite.substitution.MatcherReplacer DEBUG: found 1
org.tuckey.web.filters.urlrewrite.substitution.MatcherReplacer DEBUG: replaced sb is /appname/?delay=1
org.tuckey.web.filters.urlrewrite.RuleExecutionOutput DEBUG: needs to be forwarded to /appname/?delay=1
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: starting conf reload check
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: conf is not modified
org.tuckey.web.filters.urlrewrite.utils.ServerNameMatcher DEBUG: looking for hostname match on current server name test.example.org
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: checking for status path on /appname/
org.tuckey.web.filters.urlrewrite.UrlRewriter DEBUG: processing request for /appname/
org.tuckey.web.filters.urlrewrite.RuleBase DEBUG: Rule 0 run called with /appname/

我错过了什么？

tomcat

1 个回答

  1. Best Answer

    以全新的眼光看待这个问题后，我to为跨上下文转发设置了错误的规则。

    将其设置为

    <to type="forward" qsappend="true" context="appname">/$1?delay=1</to>

    它工作正常！嘘！

    • 0

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