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Costales
Asked: 2021-12-02 03:29:25 +0800 CST

Ansible：将字符串转换为字典

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我正在从 Tower 启动 Ansible，然后将新用户填充为文本：

{ name: user1, uid: 5000 }
{ name: user2, uid: 5001 }

我想将这些用户作为字典进行迭代，例如：

- name: Print vars
  debug:
    var: "{{ item.name }}"
  with_items: "{{ users.split('\n') }}"

但它不起作用：

TASK [Print vars] *********************************************************************************************************************
ok: [lx-test] => (item={ name: user1, uid: 5000 }) => {
    "ansible_loop_var": "item",
    "item": "{ name: user1, uid: 5000 }",
    "{ name: user1, uid: 5000 }": "VARIABLE IS NOT DEFINED!"
}
ok: [lx-test] => (item={ name: user2, uid: 5001 }) => {
    "ansible_loop_var": "item",
    "item": "{ name: user2, uid: 5001 }",
    "{ name: user2, uid: 5001 }": "VARIABLE IS NOT DEFINED!"
}

知道如何将该字符串转换为真正的字典吗？提前致谢！

ansible

1 个回答

  1. Best Answer

    更新

    下面的表达式

    users_list: "{{ users_str.splitlines()|map('from_yaml')|list }}"

    给

    users_list:
  - name: user1
    uid: 5000
  - name: user2
    uid: 5001

    适当地声明变量。

    原始答案

    该文本既不是有效的 JSON 也不是 YAML。您必须拆分行并逐行阅读字典。例如，给定文本

    users_str: |
  { name: user1, uid: 5000 }
  { name: user2, uid: 5001 }

    下面的任务

        - set_fact:
        users_list: "{{ users_list|d([]) + [item|from_yaml] }}"
      loop: "{{ users_str.splitlines() }}"

    创建字典列表

    users_list:
  - name: user1
    uid: 5000
  - name: user2
    uid: 5001

    迭代现在很简单

        - debug:
        var: item.name
      loop: "{{ users_list }}"

    给

      item.name: user1
  item.name: user2
    • 1

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