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user2680530
Asked: 2020-05-13 12:52:29 +0800 CST

在 Ansible 中构建 JSON 对象列表

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我正在尝试在 Ansible 中构建 JSON 对象的数组/列表。我的剧本是通过指定来调用的--extra-vars "userids=123456,654321"。

然后我尝试使用以下内容构建列表。“待定”只是一个占位符。我将在后面的剧本中使用从 SQL 查询中检索到的数据填充这些值。

- name: Initiate User List
      set_fact:
        all_users: []    

    - name: Add new JSON Objects to List
      set_fact:
        all_users: "{{ all_users+ [{ 'UserID': '{{ item }}', 'UserType': 'TBD', 'UserName': 'TBD' }] }}"
      loop: "{{ userids.split(',') }}"

    - name: Debug
      debug:
        var: all_users

列表排序的构建，但它跳过了列表中的第一项。这是结果输出：

TASK [Initiate User List] *************************************************************************************************************************************************************
ok: [localhost]

TASK [Add new JSON Objects to List] ******************************************************************************************************************************************************
ok: [localhost] => (item=123456)
ok: [localhost] => (item=654321)

TASK [Debug] *****************************************************************************************************************************************************************************
ok: [localhost] => {
    "all_users": [
        {
            "UserID": "654321",
            "UserType": "TBD",
            "UserName": "TBD"
        },
        {
            "UserID": "{{ item }}",
            "UserType": "TBD",
            "UserName": "TBD"
        }
    ]
}

我不确定我错过了什么。我尝试在循环任务之前执行“set_fact”以首先执行 split()，但这没有帮助。我也试过“with_items”而不是循环，没有运气

json ansible

1 个回答

  1. Best Answer

    不要使用嵌套的花括号"{{ ... {{ item }} ... }}"。正确的语法是

    all_users: "{{ all_users+ [{ 'UserID': item,
                             'UserType': 'TBD',
                             'UserName': 'TBD' }] }}"

    接下来，提交一个列表更方便userids。那么split过滤器就没有必要了。例如剧本

    shell> cat playbook.yml
- hosts: localhost
  tasks:
    - name: Initiate User List
      set_fact:
        all_users: []
    - name: Add new JSON Objects to List
      set_fact:
        all_users: "{{ all_users +
                       [{ 'UserID': item,
                          'UserType': 'TBD',
                          'UserName': 'TBD' }] }}"
      loop: "{{ userids }}"
    - name: Debug
      debug:
        var: all_users

    给

    shell> ansible-playbook -e "userids=['123456','654321']" playbook.yml
...
    "all_users": [
        {
            "UserID": "123456",
            "UserName": "TBD",
            "UserType": "TBD"
        },
        {
            "UserID": "654321",
            "UserName": "TBD",
            "UserType": "TBD"
        }
    ]

    userids如果属性UserID应存储为integertype 而不是. 从列表中的项目中删除单引号string。例如

    shell> ansible-playbook -e "userids=[123456,654321]" playbook.yml

    给出（的值周围没有引号UserID）

        "all_users": [
        {
            "UserID": 123456,
            "UserName": "TBD",
            "UserType": "TBD"
        },
        {
            "UserID": 654321,
            "UserName": "TBD",
            "UserType": "TBD"
        }
    ]

    然后使用字典创建用户列表。例如，

    shell> cat playbook.yml
- hosts: localhost
  vars:
    my_users:
      123456:
        name: Alice Admin
        type: admin
      654321:
        name: Bob Business
        type: sales
  tasks:
    - name: Initiate User List
      set_fact:
        all_users: []
    - name: Add new JSON Objects to List
      set_fact:
        all_users: "{{ all_users +
                       [{ 'UserID': item,
                          'UserType': my_users[item].type,
                          'UserName': my_users[item].name }] }}"
      loop: "{{ userids }}"
    - name: Debug
      debug:
        var: all_users

    给

    shell> ansible-playbook -e "userids=[123456,654321]" playbook.yml
...
    "all_users": [
        {
            "UserID": 123456,
            "UserName": "Alice Admin",
            "UserType": "admin"
        },
        {
            "UserID": 654321,
            "UserName": "Bob Business",
            "UserType": "sales"
        }
    ]
    • 3

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