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Jordan
Asked: 2023-12-11 22:49:21 +0800 CST

Xsd com Enumeração – Obtendo erro ao colocar o tipo de enumeração

  • 772

Estou tentando adicionar o tipo Enumeration como você pode ver abaixo. ele adiciona o tipo string, mas preciso de valores enum quando jaxb converte xsd em classe java. Usei simpletype que o converte em string, mas não tenho certeza de como alterá-lo dentro do elemento, pois se eu tentar alterá-lo, ocorrerá um erro.

<xs:element name="DeletionReq">
    <xs:complexType>
        <xs:sequence>
                <xs:element name="Id" type="xs:long"/>
                <xs:element name="isNewProcess" type="xs:boolean" default="false"/>
                <xs:element name="data" type="tns:data" nillable="true" minOccurs="0" maxOccurs="unbounded"/>
        </xs:sequence>
    </xs:complexType>
</xs:element>
<xs:complexType name="data">
    <xs:sequence>
                      <xs:element name="dataColumnName" type="xs:string" minOccurs="0" />
                      <xs:element name="dataOldValue"   type="xs:string" minOccurs="0"/>
                      <xs:element name="dataNewValue"   type="xs:string" minOccurs="0"/>
                      <xs:element name="testRecord"   type="xs:string" minOccurs="0"/>
                      <xs:element name="projId"   type="xs:string" minOccurs="0"/>
                      <xs:element minOccurs="0" name="allowedApplDataColumnNames">
                          <xs:simpleType>
                            <xs:restriction base="xs:string">
                              <xs:enumeration value="code1" />
                              <xs:enumeration value="code2" />
                              <xs:enumeration value="code3" />
                              <xs:enumeration value="code4" />
                              <xs:enumeration value="code5" />
                            </xs:restriction>
                          </xs:simpleType>
                       </xs:element>
    </xs:sequence>
</xs:complexType>
enums

2 respostas

  1. Faça um tipo explícito do seu enum:

        <xs:complexType name="data">
        <xs:sequence>
            ...
            <xs:element minOccurs="0" name="allowedApplDataColumnNames" type="tns:myEnum"/>
        </xs:sequence>
    </xs:complexType>
    
    <xs:simpleType name="myEnum">
        <xs:restriction base="xs:string">
            <xs:enumeration value="code1" />
            <xs:enumeration value="code2" />
            <xs:enumeration value="code3" />
            <xs:enumeration value="code4" />
            <xs:enumeration value="code5" />
        </xs:restriction>
    </xs:simpleType>
    • 1
  2. Best Answer

    Você pode definir o tipo fora do complexType datada seguinte forma:

    <xs:simpleType name="allowedApplDataColumnNamesType">
    <xs:restriction base="xs:string">
        <xs:enumeration value="code1" />
        <xs:enumeration value="code2" />
        <xs:enumeration value="code3" />
        <xs:enumeration value="code4" />
        <xs:enumeration value="code5" />
    </xs:restriction>
</xs:simpleType>

<xs:complexType name="data">
    <xs:sequence>
        <xs:element name="dataColumnName" type="xs:string" minOccurs="0" />
        <xs:element name="dataOldValue" type="xs:string" minOccurs="0"/>
        <xs:element name="dataNewValue" type="xs:string" minOccurs="0"/>
        <xs:element name="testRecord" type="xs:string" minOccurs="0"/>
        <xs:element name="projId" type="xs:string" minOccurs="0"/>
        <xs:element name="allowedApplDataColumnNames" type="tns:allowedApplDataColumnNamesType" minOccurs="0" />
    </xs:sequence>
</xs:complexType>
    • 0

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