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主页 / dba / 问题 / 341093
Accepted
TheLovelySausage
TheLovelySausage
Asked: 2024-07-23 00:13:24 +0800 CST2024-07-23 00:13:24 +0800 CST 2024-07-23 00:13:24 +0800 CST

按子表排序但保持父表顺序

  • 772

我目前正在尝试对两个表的结果进行排序,使得主排序字段是子表中的一个,但希望保持父表结果不被移出序列。

以下表格就是一个例子(使用 Ms SQL Server):

CREATE TABLE tier_a(
   idno INTEGER NOT NULL,
   name VARCHAR(10) NOT NULL
);

CREATE TABLE tier_b(
   idno INTEGER NOT NULL,
   tier_a_idno INTEGER NOT NULL,
   name VARCHAR(10) NOT NULL
);

INSERT INTO tier_a VALUES(3, 'C');
INSERT INTO tier_a VALUES(2, 'B');
INSERT INTO tier_a VALUES(1, 'A');

INSERT INTO tier_b VALUES(1, 1, 'A');
INSERT INTO tier_b VALUES(4, 2, 'C');
INSERT INTO tier_b VALUES(2, 1, 'B');
INSERT INTO tier_b VALUES(5, 3, 'A');
INSERT INTO tier_b VALUES(3, 1, 'C');

如果我仅按子表排序:

SELECT tier_a.name AS tier_a_name, tier_b.name AS tier_b_name
FROM tier_a
JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
ORDER BY tier_b_name ASC

我得到了我期望的:

Ascending by child

tier_a_name | tier_b_name
C           | A
A           | A
A           | B
A           | C
B           | C

Descending by child

tier_a_name | tier_b_name
B           | C
A           | C
A           | B
C           | A
A           | A

但我想要实现的是仍然保持父表的顺序:

Ascending by child

tier_a_name | tier_b_name
A           | A
A           | B
A           | C
C           | A
B           | C

Descending by child

tier_a_name | tier_b_name
A           | C
A           | B
A           | A
B           | C
C           | A

我可以用一本糟糕的手册来模拟它ORDER BY:

Ascending by child

SELECT tier_a.name AS tier_a_name, tier_b.name AS tier_b_name
FROM tier_a
JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
ORDER BY
   CASE
      -- Parent of the Lowest tier_b name (A)
      WHEN tier_a.idno = 1 THEN 1
      -- Parent of the Lowest tier_b name (A) but Higher tier_a idno
      WHEN tier_a.idno = 3 THEN 2
      -- Parent of the Highest tier_b name (C)
      WHEN tier_a.idno = 2 THEN 3
   END,
   tier_b_name ASC

Descending by child

SELECT tier_a.name AS tier_a_name, tier_b.name AS tier_b_name
FROM tier_a
JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
ORDER BY
   CASE
      -- Parent of the Highest tier_b name (C)
      WHEN tier_a.idno = 1 THEN 1
      -- Parent of the Highest tier_b name (C) but Higher tier_a idno
      WHEN tier_a.idno = 2 THEN 2
      -- Parent of the Lowestest tier_b name (A)
      WHEN tier_a.idno = 3 THEN 3
   END,
   tier_b_name DESC
sql-server
  • 2 2 个回答
  • 55 Views

2 个回答

  • Voted
  1. Best Answer
    Yano_of_Queenscastle
    2024-07-23T01:13:46+08:002024-07-23T01:13:46+08:00

    那么,你想吗ORDER BY (tier A in order of the largest/smallest tier B), (tier B)?

    对于上升,那将是:

    SELECT 
      tier_a.name AS tier_a_name, 
      tier_b.name AS tier_b_name,
      /*SMALLEST tier_b for each tier_a*/
      tier_a_ordinal = MIN(tier_b.name) OVER (PARTITION BY tier_a.name),
      /*Order of the tier_b value in the tier_a block*/
      tier_b_ordinal = ROW_NUMBER() OVER (PARTITION BY tier_a.name ORDER BY tier_b.name)
    FROM tier_a
    JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
    ORDER BY
      /*First order tier_a by the largest tier_b they have in.*/
      tier_a_ordinal ASC,
      /*If multiple tier_a's have the same largest tier_b, order then _somehow_.*/
      tier_a_name ASC,   
      /*Inside the tier_a's, order them by the tier_b*/
      tier_b_ordinal ASC; 
    

    对于降序:

    SELECT 
      tier_a.name AS tier_a_name, 
      tier_b.name AS tier_b_name,
      /*LARGEST tier_b for each tier_a*/
      tier_a_ordinal = MAX(tier_b.name) OVER (PARTITION BY tier_a.name),
      tier_b_ordinal = ROW_NUMBER() OVER (PARTITION BY tier_a.name ORDER BY tier_b.name)
    FROM tier_a
    JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
    ORDER BY
      /*First, order by tier_a's by the largest tier_b they have*/
      tier_a_ordinal DESC,  
      /*If multiple have the same largest tier_b, order them _somehow_ */
      tier_a_name DESC,  
      /*Last, order the tier_b's in that tier_a */
      tier_b_ordinal DESC; 
    

    小提琴

    • 4
  2. SergeyA
    2024-07-23T00:23:34+08:002024-07-23T00:23:34+08:00

    这就是你要找的吗?

    Ascending by child

    SELECT tier_a.name AS tier_a_name, tier_b.name AS tier_b_name
    FROM tier_a
    JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
    ORDER BY tier_a.name, tier_b_name ASC
    

    Descending by child

    SELECT tier_a.name AS tier_a_name, tier_b.name AS tier_b_name
    FROM tier_a
    JOIN tier_b ON tier_b.tier_a_idno = tier_a.idno
    ORDER BY tier_a.name, tier_b_name DESC
    
    • -2

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