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主页 / dba / 问题 / 279446
Accepted
Jeremy Thompson
Jeremy Thompson
Asked: 2020-11-10 21:47:22 +0800 CST2020-11-10 21:47:22 +0800 CST 2020-11-10 21:47:22 +0800 CST

带有动态 Case 子句的查询或如何避免 Case When

  • 772

让我们使用 CASE 子句进行日常查询,以便向您展示问题,看看当新的认证出现时我们必须如何更改查询:

select count(*) as "certCount",
CASE
when c.id = 1 then 'AWS Cloud Practitioner'
when c.id = 2 then 'AWS Alexa Skill Builder'
when c.id = 3 then 'AWS Solution Architect Associate'
when c.id = 4 then 'AWS Developer Associate'
when c.id = 5 then 'AWS SysOps Associate'
when c.id = 6 then 'AWS Solution Architect Professional'
when c.id = 7 then 'AWS DevOps Professional'
when c.id = 8 then 'AWS Security'
when c.id = 9 then 'AWS Networking'
when c.id = 10 then 'AWS Big Data'
when c.id = 11 then 'AWS Machine Learning'
ELSE 'N/A'
END AS name
from certification c
inner join qualification q on c.id = q.certificationid
group by q.certificationid, c.id

当然,我们可以生成 SQL 并以 Ad-Hoc 方式执行它。这是我过去所做的,尽管我想知道是否有另一种方式,比如某种加入方式可以避免 CASE WHENs?


下面的模式和示例数据,它在 PostGres 中,但我也对 Oracle、SQLServer 等的动态案例语句感兴趣:

 CREATE TABLE certification (
    id serial NOT NULL,
    officialcertname text NOT NULL,
    "name" text NOT NULL,
    vendorid int4 NOT NULL DEFAULT 1,
    isdeleted bool NOT NULL DEFAULT false,
    CONSTRAINT certification_pkey PRIMARY KEY (id)
);

CREATE TABLE qualification (
    id serial NOT NULL,
    employeeid int4 NOT NULL,
    certificationid int4 NOT NULL,
    date_attained timestamptz NULL,
    date_expiry timestamptz NULL,
    certurl text NULL,
    verified bool NOT NULL DEFAULT false,
    created_by text NOT NULL,
    created_date timestamptz NOT NULL,
    modified_by text NULL,
    modified_date timestamptz NULL,
    CONSTRAINT qualification_pkey PRIMARY KEY (id)
);


INSERT INTO certification (officialcertname,"name",vendorid,isdeleted) VALUES 
('AWS Certified Cloud Practitioner (CLF)','AWS Cloud Practitioner',1,false)
,('AWS Certified Alexa Skill Builder','AWS Alexa Skill Builder',1,false)
,('AWS Certified Solutions Architect - Associate (SAA)','AWS Solution Architect Associate',1,false)
,('AWS Certified Developer - Associate (DVA)','AWS Developer Associate',1,false)
,('AWS Certified SysOps Administrator - Associate (SOA)','AWS SysOps Associate',1,false)
,('AWS Certified Solutions Architect - Professional (SAP)','AWS Solution Architect Professional',1,false)
,('AWS Certified DevOps Engineer - Professional (DOP)','AWS DevOps Professional',1,false)
,('AWS Certified Security - Specialty (SCS)','AWS Security',1,false)
,('AWS Certified Networking - Specialty (SNS)','AWS Networking',1,false)
,('AWS Certified Big Data - Specialty','AWS Big Data',1,false)
;
dynamic-sql case
  • 1 1 个回答
  • 62 Views

1 个回答

  • Voted
  1. Best Answer
    Mike Petri
    2020-11-11T10:48:08+08:002020-11-11T10:48:08+08:00

    不确定您要解决什么报告问题,但看起来您可以通过简单地引用连接列来获得您所追求的。这里有几个例子:

    /* Count of certifications held by all employees */
    SELECT  c.name
            ,COUNT(1) AS certCount
    FROM    qualification AS q
            INNER JOIN certification AS c ON c.id = q.certificationid
    GROUP BY
            c.name;
    
    /* Count of certifications held, grouped by employee */
    SELECT  q.employeeid
            ,c.name
            ,COUNT(1) AS certCount
    FROM    qualification q
            INNER JOIN certification AS c ON c.id = q.certificationid
    GROUP BY
            q.employee_id
            ,c.name;
    
    • 2

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