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Accepted
AakashM
Asked: 2019-10-26 13:32:21 +0800 CST

为什么此分区助手视图会出现“输入字符串格式不正确”错误？

  • 772

我正在调查的一个数据库在其中定义了一个视图admin.View_PartitionRanges，该视图主要基于2009PartitionRanges年这篇 MSDN 博客文章中的视图。那里的视图定义如下：

CREATE VIEW [dbo].[PartitionRanges] AS
select pf.name as [partition_function],
       ps.name as [partition_scheme],
       1 as [partition_number],
       case when prv.value is null then NULL else '<' end as [relation],
       prv.value as [boundary_value],
       type_name(pp.system_type_id) as [type],
       fg.name as [filegroup],
       case when ps.name is null then NULL else N'IN USE' end as [status]
  from sys.partition_functions pf
  join sys.partition_parameters pp on pp.function_id = pf.function_id
  left join sys.partition_schemes ps on ps.function_id = pf.function_id
  left join sys.destination_data_spaces dds
    on dds.partition_scheme_id = ps.data_space_id and dds.destination_id = 1 
  left join sys.filegroups fg on fg.data_space_id = dds.data_space_id
  left join sys.partition_range_values prv
    on prv.function_id = pf.function_id and prv.parameter_id = 1 and
       prv.boundary_id = 1
 where pf.boundary_value_on_right = 1
 union all
select pf.name as [partition_function],
       ps.name as [partition_scheme],
       prv.boundary_id + cast(pf.boundary_value_on_right as int) as [partition_number],
       case when pf.boundary_value_on_right = 0 then '<=' else '>=' end as [relation],
       prv.value as [boundary_value],
       type_name(pp.system_type_id) as [type],
       fg.name as [filegroup],
       case when ps.name is null then NULL else N'IN USE' end as [status]
  from sys.partition_functions pf
  join sys.partition_range_values prv on
       prv.function_id = pf.function_id and prv.parameter_id = 1
  join sys.partition_parameters pp on pp.function_id = pf.function_id
  left join sys.partition_schemes ps on ps.function_id = pf.function_id
  left join sys.destination_data_spaces dds
    on dds.partition_scheme_id = ps.data_space_id and
       dds.destination_id = prv.boundary_id + cast(pf.boundary_value_on_right as int)
  left join sys.filegroups fg on fg.data_space_id = dds.data_space_id
 union all
select pf.name as [partition_function],
       ps.name as [partition_scheme],
       pf.fanout as [partition_number],
       case when prv.value is null then NULL else '>' end as [relation],
       prv.value as [boundary_value],
       type_name(pp.system_type_id) as [type],
       fg.name as [filegroup],
       case when ps.name is null then NULL else N'IN USE' end as [status]
  from sys.partition_functions pf
  join sys.partition_parameters pp on pp.function_id = pf.function_id
  left join sys.partition_schemes ps on ps.function_id = pf.function_id
  left join sys.destination_data_spaces dds
    on dds.partition_scheme_id = ps.data_space_id and dds.destination_id = pf.fanout 
  left join sys.filegroups fg on fg.data_space_id = dds.data_space_id
  left join sys.partition_range_values prv
    on prv.function_id = pf.function_id and prv.parameter_id = 1 and
       prv.boundary_id = pf.fanout - 1
 where pf.boundary_value_on_right = 0
 union all
select pf.name as [partition_function],
       ps.name as [partition_scheme],
       NULL, NULL, NULL, NULL,
       fg.name as [filegroup],
       case when dds.destination_id = pf.fanout + 1
            then N'NEXT USED' else N'NOT USED'
       end as [status]
  from sys.partition_functions pf
  join sys.partition_schemes ps on ps.function_id = pf.function_id
  join sys.destination_data_spaces dds
    on dds.partition_scheme_id = ps.data_space_id and
       dds.destination_id > pf.fanout
  join sys.filegroups fg on fg.data_space_id = dds.data_space_id

但是，当我SELECT *在 SSMS 中对此视图执行操作时，出现错误

An error occurred while executing batch. Error message is: 
Input string was not in a correct format.

怎么了？

sql-server partitioning

1 个回答

  1. Best Answer

    问题在于该视图使用的来源之一，系统视图sys.partition_range_values。这个视图的Value列是 type SQL_VARIANT，这可能会导致不加选择SELECT *的问题，因为 SQL 必须为结果集选择一个特定的类型，然后所有的值都需要被强制转换为该类型（感谢这篇博文提供了这种见解） .

    你可以自己看看这是否是导致你的问题的原因，方法是

    SELECT
    function_id
    , boundary_id
    , parameter_id
    , SQL_VARIANT_PROPERTY(Value, 'BaseType') AS DataType
FROM
    sys.partition_range_values
;

    如果您有多个不同DataType的 s，并且您可以想象在它们之间转换值可能会出现问题，那就是问题所在。

    要修复，您可以更新您的助手视图，而不是

    prv.value as [boundary_value]

    相反你有

    CASE SQL_VARIANT_PROPERTY(prv.Value,'BaseType')
WHEN 'datetimeoffset' THEN CAST(CAST(prv.Value AS datetimeoffset) AS varchar(30)) 
WHEN 'smallint' THEN CAST(CAST(prv.Value AS smallint) AS varchar(30)) 
-- etc as necessary for the types used to partition on in your database
ELSE SQL_VARIANT_PROPERTY(prv.Value,'BaseType')
ELSE 'Value of type ' + CAST(SQL_VARIANT_PROPERTY(prv.Value,'BaseType') AS varchar(15))
END 
    AS boundary_Value

    这将为您提供分区范围值的适当文本表示。

    • 1

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