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主页 / dba / 问题 / 242319
Accepted
Asrar Ahmad Ehsan
Asrar Ahmad Ehsan
Asked: 2019-07-09 00:30:21 +0800 CST2019-07-09 00:30:21 +0800 CST 2019-07-09 00:30:21 +0800 CST

SQL Server 中表的记录排序

  • 772

我有以下表格:

Customer (ID, Name, CountryID)

Country (ID, Name, Code)

从 Web 应用程序中,用户选择数量,Customers然后Countries系统根据这些参数显示结果。

例如,用户选择客户数量2和国家US,UK然后系统必须显示结果如下:

CustomerID    CustomerName    Country
--------------------------------------
1             A               US
2             B               US
3             C               UK
4             D               UK
.
.
.

我们怎样才能达到上述结果?

sql-server t-sql
  • 3 3 个回答
  • 99 Views

3 个回答

  • Voted
  1. Best Answer
    Akina
    2019-07-09T00:52:26+08:002019-07-09T00:52:26+08:00

    测试

    WITH
    cte1 AS ( SELECT 'US' country, 10 cnt
              UNION ALL
              SELECT 'UK', 2
              -- UNION ALL
              -- ... 
            ),
    cte2 AS ( SELECT customer.*, 
                     country.name country, 
                     ROW_NUMBER() OVER (PARTITION BY country.name 
                                        ORDER BY customer.id) rn
              FROM customer
              JOIN country on customer.country_id = country.id 
            )
    SELECT cte2.id CustomerID, cte2.name CustomerName, cte2.Country
    FROM cte2
    JOIN cte1 ON cte1.country = cte2.country
    WHERE cte2.rn <= cte1.cnt
    
    • 1
  2. Evgeniy Gribkov
    2019-07-09T07:11:10+08:002019-07-09T07:11:10+08:00

    最好的选择之一是通过 UNION ALL:

    SELECT TOP(2) c.ID AS [CustomerID], c.[Name] AS [CustomerName], cc.Code AS [Country]
    FROM Customer AS c
    INNER JOIN Country AS cc ON c.CountryID=cc.ID
    WHERE cc.Code='US'
    UNION ALL
    SELECT TOP(2) c.ID AS [CustomerID], c.[Name] AS [CustomerName], cc.Code AS [Country]
    FROM Customer AS c
    INNER JOIN Country AS cc ON c.CountryID=cc.ID
    WHERE cc.Code='UK';
    

    如有必要,您可以动态生成代码

    • 0
  3. Edgar Vazquez
    2019-07-09T07:13:01+08:002019-07-09T07:13:01+08:00

    试试这个

    --Number of Customer
    DECLARE @NumerOfCustomer INT=2
    --you need to receive the countrys list
    DECLARE @Countrys NVARCHAR(MAX)='1,2'
    
    --Simulated Table
    DECLARE @Customer TABLE (ID INT, Name NVARCHAR(50), CountryID INT)
    DECLARE @Country TABLE (ID INT, Name NVARCHAR(50), Code INT)
    
    --INSERT Customer
    INSERT INTO @Customer VALUES(1,'Test1',1)
    INSERT INTO @Customer VALUES(2,'Test2',1)
    INSERT INTO @Customer VALUES(3,'Test3',1)
    INSERT INTO @Customer VALUES(4,'Test4',2)
    INSERT INTO @Customer VALUES(5,'Test5',2)
    INSERT INTO @Customer VALUES(6,'Test6',2)
    INSERT INTO @Customer VALUES(7,'Test7',3)
    INSERT INTO @Customer VALUES(8,'Test8',3)
    
    --INSERT Country
    INSERT INTO @Country VALUES(1,'UK',1)
    INSERT INTO @Country VALUES(2,'ES',2)
    INSERT INTO @Country VALUES(3,'MX',1)
    
    --How many countries are received by means of a function Split
    DECLARE @Count INT=(SELECT COUNT(*) FROM dbo.Split(@Countrys,','))
    
    --We insert the result here
    DECLARE @TableAux TABLE(CustomerID INT,CustomerName NVARCHAR(50),Country NVARCHAR(50))
    --This is a Aux count
    DECLARE @Help INT=1
    --The Country Aux
    DECLARE @CountryAux NVARCHAR(10)
    WHILE @Help <=@Count
    BEGIN
    
    SELECT @CountryAux=(SELECT Data FROM dbo.Split(@Countrys,',') WHERE ID=@Help)
    
    INSERT INTO @TableAux
    SELECT TOP (@NumerOfCustomer)  CR.ID AS CustomerID,CR.[Name] AS CustomerName,CT.Name AS Country
    FROM @Customer CR
    INNER JOIN @Country CT ON CT.ID=CR.CountryID
    WHERE CT.ID=@CountryAux
    
    SET @Help=@Help+1
    --RESET 
    SET @CountryAux=''
    END
    
    
    --Select ALL Result
    SELECT * FROM @TableAux
    

    如果你收到的国家怎么串然后

    --Number of Customer
    DECLARE @NumerOfCustomer INT=2
    --you need to receive the countrys list
    --
    DECLARE @Countrys NVARCHAR(MAX)='UK,ES'
    
    --Simulated Table
    DECLARE @Customer TABLE (ID INT, Name NVARCHAR(50), CountryID INT)
    DECLARE @Country TABLE (ID INT, Name NVARCHAR(50), Code INT)
    
    --INSERT Customer
    INSERT INTO @Customer VALUES(1,'Test1',1)
    INSERT INTO @Customer VALUES(2,'Test2',1)
    INSERT INTO @Customer VALUES(3,'Test3',1)
    INSERT INTO @Customer VALUES(4,'Test4',2)
    INSERT INTO @Customer VALUES(5,'Test5',2)
    INSERT INTO @Customer VALUES(6,'Test6',2)
    INSERT INTO @Customer VALUES(7,'Test7',3)
    INSERT INTO @Customer VALUES(8,'Test8',3)
    
    --INSERT Country
    INSERT INTO @Country VALUES(1,'UK',1)
    INSERT INTO @Country VALUES(2,'ES',2)
    INSERT INTO @Country VALUES(3,'MX',1)
    
    --How many countries are received by means of a function Split
    DECLARE @Count INT=(SELECT COUNT(*) FROM dbo.Split(@Countrys,','))
    
    --We insert the result here
    DECLARE @TableAux TABLE(CustomerID INT,CustomerName NVARCHAR(50),Country NVARCHAR(50))
    --This is a Aux count
    DECLARE @Help INT=1
    --The Country Aux
    DECLARE @CountryAux NVARCHAR(10)
    WHILE @Help <=@Count
    BEGIN
    SELECT @CountryAux=(SELECT Data FROM dbo.Split(@Countrys,',') WHERE ID=@Help)
    
    INSERT INTO @TableAux
    SELECT TOP (@NumerOfCustomer)  CR.ID AS CustomerID,CR.[Name] AS CustomerName,CT.Name AS Country
    FROM @Customer CR
    INNER JOIN @Country CT ON CT.ID=CR.CountryID
    
    --if you receive the string then use CT.Name
    WHERE CT.Name=@CountryAux
    
    SET @Help=@Help+1
    --RESET 
    SET @CountryAux=''
    END
    
    
    --Select ALL Result
    SELECT * FROM @TableAux
    

    分割功能

    CREATE FUNCTION [dbo].[Split]
    (
    @String NVARCHAR(4000),
    @Delimiter NCHAR(1)
    )
    RETURNS TABLE 
    AS
    RETURN 
    (
    WITH Split(stpos,endpos) 
    AS(
    SELECT 0 AS stpos, CHARINDEX(@Delimiter,@String) AS endpos
    UNION ALL
    SELECT endpos+1, CHARINDEX(@Delimiter,@String,endpos+1)
    FROM Split
    WHERE endpos > 0
    )
    SELECT 'Id' = ROW_NUMBER() OVER (ORDER BY (SELECT 1)),
    'Data' = SUBSTRING(@String,stpos,COALESCE(NULLIF(endpos,0),LEN(@String)+1)-stpos)
    FROM Split
    )
    
    • 0

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