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SebMa
Asked: 2023-05-25 18:36:37 +0800 CST

CentOS7 上的 SystemD 计时器错误：无法解析日历规范，忽略：Mon..Sat *-*-* 18:00:00

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我的计时器在 CentOS7 上被系统拒绝：

$ journalctl -u synchro_ADN_To_Scality.timer --no-pager | sed 's/^.*systemd.1.: //' | sort -u
-- Logs begin at Thu 2023-04-06 10:25:28 CEST, end at Thu 2023-05-25 12:29:08 CEST. --
synchro_ADN_To_Scality.timer lacks value setting. Refusing.
[/usr/local/lib/systemd/system/synchro_ADN_To_Scality.timer:4] Failed to parse calendar specification, ignoring: Mon..Sat *-*-* 18:00:00
$ systemctl cat synchro_ADN_To_Scality.timer
# /usr/local/lib/systemd/system/synchro_ADN_To_Scality.timer
[Unit]
Description=Lancement quotidien de la Synchro des Synology ADN vers le Ring Scality
[Timer]
OnCalendar=Mon..Sat *-*-* 18:00:00
[Install]
WantedBy=timers.target

我在手册中看不到日期范围systemd.time：

$ man systemd.time | grep -F ".."
$

CentOS7 不识别日期范围吗？

bash

1 个回答

  1. Best Answer

    此功能是在 systemd 版本 231 中添加的：

    CHANGES WITH 231:

        * Calendar time specifications in .timer units now understand a ".."
          syntax for time ranges. Example: "4..7:10" may now be used for
          defining a timer that is triggered at 4:10am, 5:10am, 6:10am and
          7:10am every day.

        — Berlin, 2016-07-25
    • 1

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