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batchcoding____s
Asked: 2020-10-11 05:48:52 +0800 CST

如何使带有空格的cmd读取输入作为不同的术语/变量？

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当我希望我的批次获得输入时，我使用：

set /p myvar=Type here:

通过运行代码并使用空格输入类似这样的内容：

这是输入。

我可以将四个单词分别分配为一些变量吗，例如

1=This
2=is
3=the
4=input.

这样我就可以根据需要使用这些变量（ %1%, %2%, %3%, %4% ）？

或者还有其他输入命令吗？

windows-8.1 command-line

2 个回答

  1. @echo off && title <nul 

title .\%~nx0 && color 0a
cd /d "%~dp0" && mode 50,10
setlocal enabledelayedexpansion

>con: echo/ & set /p "_myvar=Enter your Input:"

set "_myvar_0=%_myvar: =" & set/a "_i+=1+0" & set "_myvar_!_i!=%"
<con: ^< nul rem./ && for /l %%l in (0 1 !_i!)do echo=!_myvar_%%~l! 

endlocal & goto=%:EOF

    您可以尝试使用数组，方法是在 dostips.com /by @Aacini上发布

    原始布局代码如下所示：

    set "_myvar=%_myvar: ="&set /a i+=1&set "_myvar[!i!]=%"

    我更喜欢替换[ ]一个简单的_

    另外，更改i+=为_i+=1+0，不需要预定义的set命令：set i=0

    set "_myvar_0=%_myvar: =" & set/a "_i+=1+0" & set "_myvar_!_i!=%"

    1.您可以使用由空格定义的分隔符访问所有事件。

    set "%_myvar: ="      ==>      "%_myvar:space="

    2.该方法使用一个计数器，其中限制是存储在 中的总数!_i!。

    set /a _i+=1+0

    3.使用for /L循环，您可以访问从0到极限的所有事件!_i!：

    for /l %%l in (0 1 !_i!)do...

    4.通过%%l将循环中的变量与分配给变量的名称连接起来_myvar_，就可以得到每次出现的值...

    for /l %%l in (0 1 !_i!)do echo=!_myvar_%%~l!

    在此处输入图像描述

    • 2
  2. Best Answer

    数组定义的另一种宏方法：

    @Echo off
rem /* Array macro definition occurs prior to delayed expansion being enabled */
 Set "DefUserArr=Set "#{i}=0"& Set /P "String=Enter #:"& For %%G in (!String!)Do (Set /a "#{i}=!#{i}!+1" & Set "#[!#{i}!]=%%G")"
rem /* Enable delayed expansion in order to expand the macro */
 Setlocal EnableDelayedExpansion
rem /* Supply the variable name to be used for the Array group using substring modification as the macro is expanded */
 %DefUserArr:#=Value%
rem /* Access the Group elements using the reference variable */
 Set Value[
rem /* Groups begin from a '1' index and group count is referenced via the Groupname{i} variable */
 Set Value{i}
 Endlocal

    示例输入输出：

    C:\Users\tcdou>inputA
Enter Value:one two&<> three^!^!
Value[1]=one
Value[2]=two&<>
Value[3]=three!!
Value{i}=3

    当然，如果您的脚本是为您自己以外的用户编写的，您可能至少要测试是否输入了输入，并且在使用之前定义了“数组”。下面是一个稍微更健壮的版本，它演示了一个?ArrDef测试这个的宏：

    @Echo off & Setlocal DISABLEdelayedexpansion
rem /* Array macro definition occurs prior to delayed expansion being enabled */
 Set "DefUserArr=Set "String="&For %%n in (1 2)Do if %%n==2 ((If /I Not "!Switch!" == "-A" (For /F "Tokens=1,2 Delims==" %%v in ('2^> Nul Set #[')Do Set "%%~v=" & Set "#{i}=0")) & Set /P "String=Enter #:"& For %%G in (!String!)Do (Set /a "#{i}=!#{i}!+1" & Set "#[!#{i}!]=%%~G"))Else Set Switch="
 Set "?ArrDef=For %%n in (1 2)Do if %%n==2 ( If "!#{i}!" == "" ( For %%G in (!Actions!)Do %%~G )Else If "!#{i}!" == "0" ( For %%G in (!Actions!)Do %%~G ))Else Set Actions="
rem /* Enable delayed expansion in order to expand the macro */
 Setlocal EnableDelayedExpansion
rem /* Supply the variable name to be used for the Array group using substring modification as the macro is expanded */
:Input1
 %DefUserArr:#=Value%
rem /* test if array defined */
 %?ArrDef:#=Value% "Echo/Inital input required" "Goto :Input1"
rem /* Access the Group elements using the reference variable */
 Set Value[
rem /* Groups begin from a '1' index and group count is referenced via the Groupname{i} variable */
 Set Value{i}
rem /* append to the array using the -A switch */
 %DefUserArr:#=Value%-A
 Set Value[
 Set Value{i}
rem /* Using the DefUserArr macro without the -A switch will remove any preexisting values for the supplied group name. */
:Input3
 %DefUserArr:#=Value%
 %?ArrDef:#=Value% "Echo/New input required" "Goto :Input3"
 Set Value[
 Set Value{i}
 Endlocal & Endlocal
    • 2

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