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Village
Asked: 2020-08-30 06:50:12 +0800 CST

如何使用 grep 打印行，直到匹配右括号？

  • 772

我有一个包含如下代码的文档：

Some words.

\NOTETAKING{ some text
 This is some {} text.
  This is more text \this{}.
}

Some more words.

如何使用 grep 匹配以 \NOTETAKING{ 开头的行，该括号内的所有文本，直到并包括带有匹配右括号的行？

  • NOTETAKING 可以在文档中出现多次，我需要找到第 n 次出现，例如有时搜索第 1 次出现，有时搜索第 3 次出现。
  • 它总是出现在行首。
  • 它的右括号总是单独一行。
grep brackets

1 个回答

  1. Best Answer

    如果 Perl 是您的选择，这里有一种方法可以完成这项工作。

    我假设}定义块的结尾是在一行的开头，如果之前可以有一些空格}，请使用/^\h*}/而不是/^}/

    代码：

    perl -ane 'if(/\\NOTETAKING/ ... /^}/){$counter++ if /\\NOTETAKING/; print if $counter==2}' file.txt

    输入文件：

    Some words.

\NOTETAKING{ some text 1rst occurrence
 This is some {} text.
  This is more text \this{}.
}

Some more words.
Some words.

\NOTETAKING{ some text 2nd occurrence
 This is some {} text.
  This is more text \this{}.
}

Some more words.
Some words.

\NOTETAKING{ some text 3rd occurrence
 This is some {} text.
  This is more text \this{}.
}

Some more words.

    输出：

    \NOTETAKING{ some text 2nd occurrence
 This is some {} text.
  This is more text \this{}.
}

    解释：

    perl -ane '                         # invoke Perl
if(/\\NOTETAKING/ ... /^}/){            # if we are between \NOTETAKING  & } at the beginning of line
    $counter++ if /\\NOTETAKING/;           # increment $counter if the line contains \NOTETAKING
    print if $counter==2                    # print current line, here for the 2nd occurrence, change the "2" with the occurrenec number you want to be printed
}                                       # endif
'                                   # end perl code
file.txt                            # input file
    • 1

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