主页 / coding / 问题

问题[nim-lang](coding)

Martin Hope
Sonicsmooth
Asked: 2025-01-12 12:15:49 +0800 CST
  • 5

似乎所有创建 ref 对象的示例都会创建一个副本或创建一个临时对象然后将其丢弃。如何创建对对象的引用，而不进行任何复制？我明确尝试在没有样式声明的情况下执行此操作type Rect = ref object...。

看起来new Rect是 类型ref Rect。显然这进行了一些分配。

我见过的每个例子都大致如此：

type Rect = object
  x: int
  y: int

# Basic, no refs; create and assign
var r0: Rect = Rect(x:10, y:20)

# The usual example; this seems to create extra object, copy values, then throw away
var r1: ref Rect = new Rect  # Creates default Rect
r1[] = Rect(x:10, y:20)      # Create desired Rect, copy, and throw away first Rect
                             # Or Create desired Rect, assign, and throw away first Rect

# This is what I'd like to do.  None of these attempts works
var r2: ref Rect = new Rect(x:10, y:20)

# Or this
var r3: ref Rect = ref Rect(x:10, y:20)

# Or this
var r4: ref Rect = ref new Rect(x:10, y:20)

# Or this
var r5: ref Rect = Rect(x:10, y:20)

那么，是否可以声明一个 ref 并将其分配给新实例，而无需复制和/或创建额外的一次性对象？最好在一行中完成此操作，但这不是硬性要求。

谢谢

nim-lang