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Accepted
Harry
Asked: 2025-02-25 15:14:17 +0800 CST

使用给定目录规范化包含当前目录的文件路径字符串

  • 772

是否可以将包含当前目录 ( .) 的文件路径字符串与给定目录进行规范化。例如，文件路径 => ./abcd.txt，给定目录 => /a/b/c。生成的文件路径的预期结果是/a/b/c/abcd.txt。

fn main() {
    let file_path = "./abcd.txt";
    let cur_dir = "/a/b/c";
    
    let path = std::fs::canonicalize(file_path).unwrap();
    println!("{:#?}", path);
}

输出

thread 'main' panicked at src/main.rs:5:49:
called `Result::unwrap()` on an `Err` value: Os { code: 2, kind: NotFound, message: "No such file or directory" }
note: run with `RUST_BACKTRACE=1` environment variable to display a backtrace
rust

1 个回答

  1. Best Answer

    使用Path::join：

    let path = Path::new (cur_dir).join (file_path).canonicalize();
    • 2

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