主页 / coding / 问题 / 79432553
Accepted
kkudi
Asked: 2025-02-12 17:39:18 +0800 CST

将 kdb 字典转换为列表

  • 772

给定一个如下所示的字典：

`a`b`c!((0;3); (1;4); enlist 2)

I'd like to find an elegant way to get the following list as a result: 

`a (index 0)
`b (index 1)
`c (index 2)
`a (index 3)
`b (index 4)
dictionary

3 个回答

  1. Best Answer
    q)d:`a`b`c!((0;3); (1;4); enlist 2)
q){exec k from `v xasc ungroup ([] k:key x;v:value x)} d
`a`b`c`a`b
    • 3

  2. 还有一个快速、简短的解决方案：

    q)where[count each d]iasc raze d
`a`b`c`a`b
    • 3

  3. 不确定是否优雅，但这应该可行

    d:`a`b`c!((0;3); (1;4); enlist 2)
(raze (value count each d)#'key[d]),'raze d
`a 0
`a 3
`b 1
`b 4
`c 2

    至于优雅，这个相当优雅

    raze key[d],''d
`a 0
`a 3
`b 1
`b 4
`c 2
    • 2

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