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主页 / coding / 问题 / 79422705
Accepted
Eliz A Purves
Eliz A Purves
Asked: 2025-02-08 13:57:03 +0800 CST2025-02-08 13:57:03 +0800 CST 2025-02-08 13:57:03 +0800 CST

如何向联合查询添加参数

  • 772

我在这里找到了以下查询,发现它很有用。使查询适用于我的数据库后,我现在想向其中添加一个参数以过滤掉不需要的记录 - 该参数所需的表名为 Season,与成员表的联接为 seasons.idseasons = members.members id no,参数为 WHERE (((seasons.Season)=[enter season]))。

Select  (tMin.Initial1 + ' and ' + tMax.Initial1) As initial, tMax.surname1 As surname, tMax.[first line address], tMax.[second line address], tMax.town, tMax.postcode, tMax.GroupCount From (Select Distinct Max(initial) As initial1, Max(surname) As surname1,[first line address], [second line address], town, postcode, Count() As  GroupCount From members Group By [first line address], [second line address], town, postcode Having Count() = 2) As tMax Inner Join

   (Select Distinct Min(initial) As initial1, Min(surname) As surname1, [first line address],[second line address], town, postcode, Count(*) As GroupCount
   From members
   Group By [first line address], [second line address], town, postcode
   Having Count(*) = 2) As tMin

           On (tMax.[first line address] = tMin.[first line address]) And 
              (IIf(IsNull(tMax.[second line address]), '', tMax.[second line address]) = IIf(IsNull(tMin.[second line address]), '', tMin.[second line address])) And 
              (tMax.town = tMin.town) And  
               (tMax.postcode = tMin.postcode)

UNION ALL Select Max(initial) As initial1, Max(surname) As surname1, [first line address], [second line address], town, postcode, Count() As GroupCount From members Group By [first line address], [second line address], town, postcode Having Count() = 1 Or Count(*) > 2

ORDER BY surname, initial, town, postcode;

不确定参数应该放在代码中的什么位置。你能帮忙吗?

ms-access
  • 1 1 个回答
  • 20 Views

1 个回答

  • Voted
  1. Best Answer
    Gustav
    2025-02-08T16:30:43+08:002025-02-08T16:30:43+08:00

    尝试一下:

    Select  
        (tMin.Initial1 + ' and ' + tMax.Initial1) As initial, 
        tMax.surname1 As surname, 
        tMax.[first line address], 
        tMax.[second line address], 
        tMax.town, tMax.postcode, 
        tMax.GroupCount 
    From 
        (Select Distinct 
            Max(initial) As initial1, 
            Max(surname) As surname1,
            [first line address], 
            [second line address], 
            town, postcode, 
            Count() As  GroupCount 
        From 
            members
        Inner Join
            Seasons
            On members.memberid = Seasons.idseasons
        Where
            Seasons.season = [Enter Season]
        Group By 
            [first line address], 
            [second line address], 
            town, 
            postcode 
        Having Count() = 2) As tMax 
    
    Inner Join
    
        (Select Distinct 
            Min(initial) As initial1, 
            Min(surname) As surname1, 
            [first line address],
            [second line address], 
            town, 
            postcode, 
            Count(*) As GroupCount
        From 
            members
        Inner Join
            Seasons
            On members.memberid = Seasons.idseasons
        Where
            Seasons.season = [Enter Season]
        Group By 
            [first line address], 
            [second line address], 
            town, 
            postcode
        Having Count(*) = 2) As tMin
    
        On  (tMax.[first line address] = tMin.[first line address]) And 
            (IIf(IsNull(tMax.[second line address]), '', tMax.[second line address]) = IIf(IsNull(tMin.[second line address]), '', tMin.[second line address])) And 
            (tMax.town = tMin.town) And  
            (tMax.postcode = tMin.postcode)
    
    UNION ALL 
    
    Select 
        Max(initial) As initial1, 
        Max(surname) As surname1, 
        [first line address], 
        [second line address], 
        town, 
        postcode, 
        Count() As GroupCount 
    From 
        members 
    Inner Join
        Seasons
        On members.memberid = Seasons.idseasons
    Where
        Seasons.season = [Enter Season]
    Group By 
        [first line address], 
        [second line address], 
        town, 
        postcode 
    Having 
        Count() = 1 Or Count(*) > 2
    ORDER BY 
        surname, 
        initial, 
        town, 
        postcode;
    
    • 0

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