在以下代码中,只要中的值TextField
不是双精度值,就会显示消息“不是双精度”。这是通过此 Flutter 应用程序中的方法完成的。我希望它们显示在警报对话框中,而不是像这里显示的消息。我该如何实现?谢谢。
import 'package:flutter/material.dart';
void main() {
runApp(const MyApp());
}
class MyApp extends StatelessWidget {
const MyApp({super.key});
@override
Widget build(BuildContext context) {
return MaterialApp(
title: 'Flutter Demo',
theme: ThemeData(
colorScheme: ColorScheme.fromSeed(seedColor: Colors.deepPurple),
useMaterial3: true,
),
home: const MyHomePage(title: 'Flutter Demo Home Page'),
);
}
}
class MyHomePage extends StatefulWidget {
const MyHomePage({super.key, required this.title});
final String title;
@override
State<MyHomePage> createState() => _MyHomePageState();
}
class _MyHomePageState extends State<MyHomePage> {
late TextEditingController myController;
String text = "INIT";
bool is_double_input(String str) {
double a = 0.0;
int exception_caught = 0;
try {
a = double.parse(str);
} catch (e) {
exception_caught++;
} finally {
if (exception_caught == 0) {
return true;
} else {
return false;
}
}
}
void setMessage(String myStr) {
// text = myStr;
if (is_double_input(myStr)) {
text = myStr;
} else {
text = "Not A Double";
}
}
@override
void initState() {
super.initState();
myController = TextEditingController();
}
@override
void dispose() {
myController.dispose();
super.dispose();
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
backgroundColor: Theme.of(context).colorScheme.inversePrimary,
title: Text(widget.title),
),
body: Column(
children: [
Expanded(
child: TextField(
controller: myController,
keyboardType: TextInputType.number,
onChanged: (value) {
setState(() {
setMessage(value);
});
},
),
),
Expanded(
child: Text("MESSAGE: ${text}"),
),
],
),
);
}
}
更新 01:虽然问题现在已经得到解答,但我还添加了其他代码showDialog
来弹出警报对话框,但这不起作用。我必须触摸警报对话框之外的内容才能关闭对话框。有人能帮忙吗?代码如下:
showDialog(
context: context,
builder: (context) => AlertDialog(
title: const Text('Error'),
content: const Text('Not a Double'),
actions: [
TextButton(
onPressed: () {
Navigator.of(context).pop;
},
child: const Text("Ok"),
),
],
),
);
您可以将 BuildContext 发送到 setMessage 方法,然后在 else 中显示所需的对话框: