在汇编中，添加从终端输入的两个数字时遇到困难

1. 参数int_to_string指向​​result_buffer
2. 它向后迭代
3. 当它返回时，rsi[正确地] 指向结果 ascii 字符串（比起开头来更接近末尾）。result_buffer

例如，如果我们输入23和36，则加法的结果将是59

其result_buffer内容如下：

因此，打印时我们应该只使用返回的值rsi，而不是执行以下操作：

lea rsi, [result_buffer]    # Address of result_buffer

以下是更正后的代码：

.global _start           # Declare the global entry point
.intel_syntax noprefix   # Use Intel assembly syntax without prefixes

.section .bss            # Reserve uninitialized space for buffers
buffer1: .space 20
buffer2: .space 20
result_buffer: .space 20

.section .text
_start:
    # Read the first number
    mov rax, 0          # sys_read
    mov rdi, 0          # File descriptor: stdin
    lea rsi, [buffer1]
    mov rdx, 20         # Max bytes to read
    syscall
    mov byte ptr [rsi + rax], 0 # null terminate the input buffer

    lea rsi, [buffer1]
    call string_to_int
    mov r8, rax         # Store the first integer in r8

    # Read the second number
    mov rax, 0          # sys_read
    mov rdi, 0          # File descriptor: stdin
    lea rsi, [buffer2]
    mov rdx, 20         # Max bytes to read
    syscall
    mov byte ptr [rsi + rax], 0

    lea rsi, [buffer2]  # Use buffer2 for the second input
    call string_to_int
    mov r9, rax         # Store the second integer in r9

    add r8, r9          # r8 = r8 + r9

    # Convert the result back to a string
    mov rax, r8         # Move the result into rax
    lea rsi, [result_buffer + 19]  # Point to the end of result_buffer
    call int_to_string

    # Calculate the string length (RCX holds the number of digits)
    mov rdx, rcx

    # Write the result
    mov rax, 1                  # sys_write
    mov rdi, 1                  # File descriptor: stdout
# FIX: do _not_ do this
    ###lea rsi, [result_buffer]    # Address of result_buffer
    mov rdx, rcx                # number of digits in result
    syscall                     # Perform system call

    # Exit
    mov rax, 60         # sys_exit
    xor rdi, rdi        # Exit code: 0
    syscall

# Subroutine: string_to_int
# Converts a null-terminated string to an integer
# Input: RSI points to the string
# Output: RAX contains the integer value
string_to_int:
    xor rax, rax    # Clear rax (result)
    xor rcx, rcx    # Clear rcx (multiplier, initially 0)

convert_loop:
    movzx rdx, byte ptr [rsi]   # Load byte from the string
    cmp rdx, 10                 # Check for newline (ASCII '\n')
    je convert_done             # Exit loop on newline
    sub rdx, '0'                # Convert ASCII to digit (0-9)
    imul rax, rax, 10           # Multiply result by 10
    add rax, rdx                # Add the current digit to the result
    inc rsi                     # Move to the next character
    jmp convert_loop

convert_done:
    ret

# Subroutine: int_to_string
# Converts an integer to a null-terminated string
# Input: RAX contains the integer, RSI points to the buffer
# Output: The buffer contains the string representation
int_to_string:
    xor rcx, rcx            # Digit counter (RCX will store the length)
    xor rbx, rbx            # Temporary register
convert_to_str:
    xor rdx, rdx            # Clear RDX for division
    mov rbx, 10             # Divisor
    div rbx                 # RAX = RAX / 10, RDX = remainder
    add dl, '0'             # Convert remainder to ASCII
    dec rsi                 # Move backwards in buffer
    mov [rsi], dl           # Store ASCII character
    inc rcx                 # Increment digit counter
    test rax, rax           # Check if RAX is 0
    jnz convert_to_str      # Continue if not zero

    # Null-terminate the string
    mov byte ptr [rsi + rcx], 0  # Null-terminate the string
    ret