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Matt Schwartz
Asked: 2024-11-03 09:29:38 +0800 CST

Web API 中响应 JSON 周围的方括号

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我已经使用 Swagger 构建了一个 C# Web API。它在此链接上启动并运行： https: //www.vijilcomm.com/api/swagger/index.html。

当我击中它时，例如像这样：

https://www.vijilcomm.com/api/VijilconOn?SerialNumber=12345&IPAddress=99.41.190.178

我收到的回复带有方括号。

[
    {
        "serialNumber": "12345",
        "ipAddress": "99.41.190.178",
        "heartbeatWait": 0,
        "alertSoundTime": 0,
        "fullBatteryLevel": 0,
        "middleBatteryLevel": 0,
        "lowBatteryLevel": 0,
        "criticalBatteryLevel": 0,
        "tooHardMovement": 0,
        "unitID": "",
        "reportPhone": "",
        "action": "Device not found"
    }
]

我知道 JSON 中的方括号表示数组。它看起来像是将其输出为数组或类似的东西。

这是带有方括号的响应的有效 JSON 吗，或者我的代码有问题？

我的控制器有以下代码：

[HttpGet(Name = "VijilconOn")]
public IEnumerable<VijilconOn> Get(string SerialNumber, string IPAddress)
{
     return Enumerable.Range(1, 1).Select(index => new VijilconOn
     {
         HeartbeatWait = (Functions.ReturnIntFieldValue("HeartbeatWait", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         AlertSoundTime = (Functions.ReturnIntFieldValue("AlertSoundTime", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         FullBatteryLevel = (Functions.ReturnIntFieldValue("FullBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         MiddleBatteryLevel = (Functions.ReturnIntFieldValue("MiddleBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         LowBatteryLevel = (Functions.ReturnIntFieldValue("LowBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         CriticalBatteryLevel = (Functions.ReturnIntFieldValue("CriticalBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         TooHardMovement = (Functions.ReturnIntFieldValue("TooHardMovement", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         UnitID = Functions.ReturnFieldValue("FriendlyName", "Devices", "[SerialNumber]='" + SerialNumber + "'").ToString(),
         ReportPhone = Functions.ReturnFieldValue("ReportPhone", "Devices", "[SerialNumber]='" + SerialNumber + "'").ToString(),
         IPAddress = Functions.RecordIPAddress(SerialNumber,IPAddress).ToString(),
         Action = Functions.CheckIn(SerialNumber, "ON").ToString(),
         SerialNumber = SerialNumber
     })
     .ToArray();
}

在我看来，将其输出为数组是合理的。我的问题是 - 我在这里做错了什么吗，或者 JSON 以这种方式输出是否合适？

谢谢你的帮助！这是我的第一个 REST JSON Web API，所以我不确定我是否走在正确的轨道上，或者是否有问题。谢谢！

我尝试使用上面的代码和 swagger，JSON 的输出与描述一致。我不确定是否必须更改控制器函数的行为方式，或者是否可以保持原样...

c#

1 个回答

  1. Best Answer

    如果您希望将响应作为数组，则您的代码看起来不错。

    但是如果你想返回单个对象，你不必使用IEnumerable。你可以创建一个对象并返回它，而不是创建Enumerable.Range(1,1)。

     [HttpGet(Name = "VijilconOn")]
 public VijilconOn Get(string SerialNumber, string IPAddress)
 {
     return new VijilconOn
     {
         HeartbeatWait = (Functions.ReturnIntFieldValue("HeartbeatWait", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         AlertSoundTime = (Functions.ReturnIntFieldValue("AlertSoundTime", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         FullBatteryLevel = (Functions.ReturnIntFieldValue("FullBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         MiddleBatteryLevel = (Functions.ReturnIntFieldValue("MiddleBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         LowBatteryLevel = (Functions.ReturnIntFieldValue("LowBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         CriticalBatteryLevel = (Functions.ReturnIntFieldValue("CriticalBatteryLevel", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         TooHardMovement = (Functions.ReturnIntFieldValue("TooHardMovement", "Devices", "[SerialNumber]='" + SerialNumber + "'")),
         UnitID = Functions.ReturnFieldValue("FriendlyName", "Devices", "[SerialNumber]='" + SerialNumber + "'").ToString(),
         ReportPhone = Functions.ReturnFieldValue("ReportPhone", "Devices", "[SerialNumber]='" + SerialNumber + "'").ToString(),
         IPAddress = Functions.RecordIPAddress(SerialNumber,IPAddress).ToString(),
         Action = Functions.CheckIn(SerialNumber, "ON").ToString(),
         SerialNumber = SerialNumber
     };
 }
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