发现 org.hibernate.InstantiationException：无法实例化抽象类或接口，但在恢复所有更改后仍然发生

我有一个抽象类：

@Entity
@Table(name = "cas_base_accounts", schema = "connectors_account_service")
@Inheritance(strategy = InheritanceType.JOINED)
@Data
@SuperBuilder
@NoArgsConstructor
public abstract class BaseAccount {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(unique = true)
    private Integer id;
//some fields here

还有两个子类：

@Entity
@Table(name = "cas_simple_auth_accounts", schema = "connectors_account_service")
@Inheritance(strategy = InheritanceType.JOINED)
@Data
@ToString(callSuper = true)
@EqualsAndHashCode(callSuper = true)
@NoArgsConstructor
@SuperBuilder
public class SimpleAuthAccount extends BaseAccount {


    @Id
    @GeneratedValue
    private Integer id;

    @NotNull
    @JsonIgnore
    private String clientId;

    @NotNull
    @JsonIgnore
    private String clientSecret;
//some other fields

和：

@Entity
@Table(name = "cas_oauth_accounts", schema = "connectors_account_service")
@Inheritance(strategy = InheritanceType.JOINED)
@Data
@ToString(callSuper = true)
@EqualsAndHashCode(callSuper = true)
@NoArgsConstructor
@SuperBuilder
public class OAuthAccount extends BaseAccount {

    @Id
    @GeneratedValue
    private Integer id;

    @JsonIgnore
    private String state;

    @JsonIgnore
    private LocalDateTime stateExpirationTime;

    @Transient
    private String tokenLink;
//some fields

当我运行简单的 GET 请求时http://localhost:8889/accountservice/accountIds?cabinetId=12收到错误：

threw exception [Request processing failed; nested exception is org.springframework.orm.jpa.JpaSystemException: Cannot instantiate abstract class or interface:  : 
test.connectorsaccountservice.accountservice.model.BaseAccount; nested exception is org.hibernate.InstantiationException: Cannot instantiate abstract class or interface:  : test.connectorsaccountservice.accountservice.model.BaseAccount] 

cabinetId = 12 的实体始终是 SimpleAuthAccount。例如，当我运行 cabinetId = 10 时，它返回正确的结果。在这种情况下，id != 12（和 21）的实体是 OauthAccount。

说明这个方法出错了：

    public Mono<List<Integer>> getAccountIds(Integer cabinetId) {
        return findServiceByCabinetId(cabinetId)
                .then(Mono.fromCallable(() -> baseAccountRepository.findByCabinetId(cabinetId)))
                .flatMapIterable(e -> e)
                .filter(oAuthAccount -> !oAuthAccount.getIsDeleted()
                        && UserStatus.ENABLED.equals(oAuthAccount.getUserStatus()))
                .map(BaseAccount::getId)
                .collectList();
    }

在这一行：

.then(Mono.fromCallable(() -> baseAccountRepository.findByCabinetId(cabinetId)))

存储库：

public interface BaseAccountRepository extends JpaRepository<BaseAccount, Integer> {

    Optional<BaseAccount> findByIdAndCabinetId(Integer accountId, Integer cabinetId);

    Optional<BaseAccount> findByCabinetIdAndAccountLogin(Integer cabinetId, String accountLogin);

    List<BaseAccount> findByCabinetId(Integer cabinetId);

简单身份验证帐户存储库：

@Repository
public interface SimpleAuthAccountRepository extends
        JpaRepository<SimpleAuthAccount, Integer>,
        CustomAccountRepository<SimpleAuthAccount, Integer> {

    @Query("SELECT a FROM SimpleAuthAccount a " +
           "JOIN BaseCabinet c ON a.cabinetId = c.id " +
           "WHERE " +
           "(:realmId IS NULL OR a.realmId = :realmId) AND " +
           "(:accountLogin IS NULL OR a.accountLogin = :accountLogin) AND " +
           "(:accountId IS NULL OR a.id = :accountId) AND " +
           "(:cabinetId IS NULL OR a.cabinetId = :cabinetId) AND " +
           "(:isDeleted IS NULL OR a.isDeleted = :isDeleted) AND " +
           "((:advertiserIds) IS NULL OR a.advertiserId IN (:advertiserIds)) " +
           "ORDER BY c.description, a.accountLogin")
    List<SimpleAuthAccount> findAccounts(
            @Param("realmId") Integer realmId,
            @Param("accountLogin") String accountLogin,
            @Param("accountId") Integer accountId,
            @Param("cabinetId") Integer cabinetId,
            @Param("isDeleted") Boolean isDeleted,
            @Param("advertiserIds") Set<Integer> advertiserIds
    );

}

顺便说一句，之前好像可以，但我做了一些更改。发生此错误后，我恢复了所有更改，但错误仍然发生。在这些更改中，我没有触及本文中的任何类，只触及了其他类。

如何修复它？为什么会发生这种情况，为什么在恢复更改后仍然会发生这种情况？我想添加@DiscriminatorColumn和@DiscriminatorValue会有所帮助？对我来说，现有的列cabinetId就很好了@DiscriminatorColumn，但如果我有一个 SimpleAuthAccount 的 id 数组和 OAuthAccount 的 id 数组，我该如何为其设置值？我真的不想在这个表中添加另一列。但当然，如果这里没有更多的解决方案，我可以添加像auth_type和设置SIMPLE_AUTH这些OAUTH类的列。