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Paul-ET
Asked: 2024-08-15 19:53:58 +0800 CST

对树形视图应用程序的第一列进行排序失败

  • 772

我使用了教程中的示例来对树形视图中的列进行排序。它适用于第 2 列和第 3 列，但不适用于第 1 列。如果我单击标题，我会收到此错误：

Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Python311\Lib\tkinter\__init__.py", line 1967, in __call__
    return self.func(*args)
           ^^^^^^^^^^^^^^^^
  File "D:\...\Test_Treeview_book.py", line 20, in <lambda>
    tv.heading('#0', text='Name', command=lambda: sort(tv, '#0'))
                                                  ^^^^^^^^^^^^^^
  File "D:\...\Test_Treeview_book.py", line 14, in sort
    itemlist.sort(key=lambda x: tv.set(x, col))
  File "D:\...\Test_Treeview_book.py", line 14, in <lambda>
    itemlist.sort(key=lambda x: tv.set(x, col))
                                ^^^^^^^^^^^^^^
  File "C:\Python311\Lib\tkinter\ttk.py", line 1434, in set
    res = self.tk.call(self._w, "set", item, column, value)
          ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
_tkinter.TclError: Display column #0 cannot be set

我有这个小测试程序作为参考，但找不到故障原因。我很感谢任何解决这个问题的提示，或者根本无法对第一列进行排序，因为它是一棵树？

import tkinter as tk
from tkinter import ttk
from pathlib import Path

root = tk.Tk()

root.grid_rowconfigure(0, weight=1)
root.grid_columnconfigure(0, weight=1)

paths = Path('.').glob('**/*')

def sort(tv, col): # Doesn't work on 1st column '#0'
    itemlist = list(tv.get_children(''))
    itemlist.sort(key=lambda x: tv.set(x, col))
    for index, iid in enumerate(itemlist):
        tv.move(iid, tv.parent(iid), index)

tv = ttk.Treeview(root, columns=['size','modified'], selectmode=None)

tv.heading('#0', text='Name', command=lambda: sort(tv, '#0'))
tv.heading('size', text='Size', anchor='center', command=lambda: sort(tv, 'size'))
tv.heading('modified', text='Modifies', anchor='center', command=lambda: sort(tv, 'modified'))

tv.column('#0', stretch = True, anchor='w')
tv.column('size', width=100, anchor='center') 
tv.column('modified',anchor='center')

tv.grid_rowconfigure(0, weight=1)
tv.grid_columnconfigure(0, weight=1) 
tv.grid(row=0, column=0, sticky='nsew')
#tv.pack(expand=True, fill='both')

for path in paths:
    meta = path.stat()
    parent = str(path.parent)
    if parent == '.':
        parent = ''
               
    tv.insert(parent, 'end', iid=str(path), text=str(path.name), values=[meta.st_size, meta.st_mtime])

scrollbar = ttk.Scrollbar(root, orient=tk.VERTICAL, command=tv.yview)
tv.configure(yscrollcommand=scrollbar.set)
scrollbar.grid(row=0, column=1, sticky='nse') #scrollbar goes not to the left!
        
root.mainloop()
sorting

1 个回答

  1. Best Answer

    正如错误所说，您不能.set()在列"#0"（树列）上使用。

    改用.item()：

    def sort(tv, col):
    itemlist = list(tv.get_children(''))
    if col == '#0':
        itemlist.sort(key=lambda x: tv.item(x, 'text'))
    else:
        itemlist.sort(key=lambda x: tv.set(x, col))
    for index, iid in enumerate(itemlist):
        tv.move(iid, tv.parent(iid), index)
    • 1

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